Put the number of daughters as x and number of sons as y.
For the first half of the statement:
Number of sisters any daughter has = x-1 ( because you can't be your own sibling)
Number of brothers = y
y=x-1.
For the second half:
Number of sisters any son has = x
Number of brothers any son has = y-1
3(y-1)=x
Solve as system of equations.
3y-3=x
3(x-1)-3=x
3x-3-3=x
2x=6
x=3
y=x-1=3-1=2
3 daughters and 2 sons.
Hope this helps!
Your fortune is "You can't have everything...where would you put them all?"
Answer:
2(2x + 5)(2x - 5)
Step-by-step explanation:
2(2x + 5)(2x - 5)
= (4x + 10)(2x - 5)
= 8x² - 20x + 20x - 50
= 8x² - 50
Answer:
x=-3
Step-by-step explanation:
2 x - 3 y = -12.
4 x + y = -10.
Answer:
10
Step-by-step explanation:
<em>10 + 10 = 2x</em>
<em>2x = 20</em>
<em>10 + 10 = 20</em>
<em>x = 10</em>
have a nice day and mark me brainliest! :)
