The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
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Answer:
y-4=4(x+1)
Step-by-step explanation:
y-y1=m(x-x1)
m=4
y-4=4(x-(-1))
y-4=4(x+1)
Answer:1.799908×10^1
Step-by-step explanation:
18-0.00092
=17.99908
In standard form=1.799908×10^1
