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olga55 [171]
3 years ago
8

A student brings whole cherry and cheese danishes to his class for his birthday. The number of cherry danishes he brings is at l

east 3 more than 2/3 the number of cheese danishes, but no more than twice the number of cheese danishes. Find the smallest possible value for the total number of danishes he brings
Mathematics
1 answer:
Elodia [21]3 years ago
7 0

Answer:

2/3 times 3

Step-by-step explanation:

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The ratio of boys to girls in a class is 3:5 what fraction are girls​
Tpy6a [65]
Answer: 5

“of boys to girls”
( 3 ) : ( 5 )
6 0
2 years ago
Consider the following figure.
kirill [66]

Answer:

80 units.

Step-by-step explanation:

The rectangle ABCD is drawn and attached in the image below. The diagonal BD measures 100 units, the side BC measures 60 units.  We need to find the measure of side DC which is represented by x in the figure.

Note that a Right Angled Triangle DCB is being formed with BD as the hypotenuse and sides BC and DC as its two legs. The Pythagoras Theorem relates the length of hypotenuse and the two legs of the Right Angled Triangle as:

c^{2}=a^{2}+b^{2}

c is the length of hypotenuse = 100

a is the length of one leg = 60

b is the length of second leg = x

Using these values, we get:

100^{2}=60^{2}+x^{2}\\\\ x^{2}=100^{2}-60^{2}\\\\ x^{2}=6400\\\\ x = 80

Therefore, measure of the side DC is 80 units

7 0
3 years ago
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
2 years ago
Which pair of expressions are equivalent?
gladu [14]
Don’t listen to the other person the answer is C.

x+x+x+x would be 4x. x^4 would be 4 times 4 times 4 times 4.
8 0
2 years ago
4.8n-1.4-6=4.12 with work
Kitty [74]
-1.4-6=-7.4
4.12+7.4=11.52
4.8n=11.52
11.52 ÷ 4.8n=2.4
n=2.4
7 0
3 years ago
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