Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
3/7
6 divided by 2 equals 3
14 divided by 2 equals 7
ANSWER: 2j-61
j = Jenny's age
Answer:
He earn $535.00 in the 5% account
Step-by-step explanation:

I = interest amount
p = $10 700
r = 5%
t = 1 year
I = (10700×5×1)/100
= $535.00
(Correct me if i am wrong)
Answer:
Step-by-step explanation:
Hi guy I just wanted to say have a very good day and I hope you are alright today and I hope this helped out your day alright peace out