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Norma-Jean [14]
3 years ago
7

Andrew invests $9,000 at the end of each year for 20 years. The rate of interest Andrew gets is 8% annually. Using the tables fo

und in the textbook, determine the final value of Andrew's investment at the end of the twentieth year on this ordinary annuity.
Mathematics
2 answers:
jok3333 [9.3K]3 years ago
4 0

Andrew invests $9,000 at the end of each year for 20 years. The rate of interest Andrew gets is 8% annually. Using the tables found in the textbook, determine the final value of Andrew's investment at the end of the twentieth year on this ordinary annuity.

R/ $411,858

lakkis [162]3 years ago
3 0
At the end of the 20 years, Andrew receives $41,948.61 
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Trying to find volume of a right circular cone.
viva [34]

Volume of the cone is 117.5 π ft³

<u>Step-by-step explanation:</u>

Lateral area of the cone = πrs

s is the slant height = 15 ft

From the above formula, we can find the radius as, 5 ft.

Volume of the cone = π r² h/3

s = √ (5²+ h²)

Squaring on both sides, we will get,

s² = 15² = (5² + h²)

 15² - 5² = h²

225 - 25 = 200 = h²

h = √200 = 14.1 ft

Volume = π × 5² × 14.1  / 3 = 117.5 π ft³

8 0
2 years ago
The weight of oranges growing in an orchard is normally distributed with a mean weight of 3.5 oz. and a standard deviation of 0.
Andreas93 [3]

Answer:

(3 oz ; 4oz)

Step-by-step explanation:

Given that :

Mean = 3.5 oz

Standard deviation = 0.5 oz

According to the empirical rule ; 68% is 1 standard deviation from the mean.

Hence, the interval that would represent the middle 68% will be:

(3.5 oz - 0.5 oz) ; (3.5 oz + 0.5oz)

(3 oz ; 4oz)

7 0
2 years ago
The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha
GuDViN [60]

Answer:106.63%.

Step-by-step explanation:To find the percentage of the price per ounce of gold increase we will use % increase formula.Therefore, the price of per ounce of gold increased by 106.63%.

7 0
1 year ago
72 greater than r is less than −432
pshichka [43]

its Greater than

Step-by-step explanation:

the 72 is a positive and -432 is a negative cause it has a minus

6 0
2 years ago
Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p
Ymorist [56]

Answer:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,7)

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

B\sim Exp(\lambda=\frac{1}{30 min})

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

E(A +B)

Since the two random variables are assumed independent, then we have this

E(A+B) = E(A)+E(B)

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{1+7}{2}=4 hours

The expected value for the exponential distirbution is given by :

E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx

If we use the substitution y=\lambda x we have this:

E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}

Where X represent the random variable and \lambda the parameter. If we apply this formula to our case we got:

E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

And in order to find the variance for the random variable A+B we can find the individual variances:

Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2

Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2

We have the following property:

Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)

Since we have independnet variable the Cov(A,B)=0, so then:

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

3 0
3 years ago
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