This problem is all about bases and exponents. Because we have a quotient and the bases are both 5's, that means that we can use the rule of exponents for quotients to rewrite and simplify:
That's the simplification as long as you are "allowed" to leave the exponent as a negative number.
It’s 20000 but not sure about it
Answer:
0 would be your answer!!!
:)
Answer:
![3\sqrt[3]{x-3}-5](https://tex.z-dn.net/?f=3%5Csqrt%5B3%5D%7Bx-3%7D-5)
Step-by-step explanation:
You can factor out the common term of 27 from 81*
![\sqrt[3]{27(x-3)}-5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%28x-3%29%7D-5)
Separate
![\sqrt[3]{27}\sqrt[3]{x-3}-5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%5Csqrt%5B3%5D%7Bx-3%7D-5)
Simplify ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
**
Finito. Nothing further can be done
*factor out 27
**![\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D3)
because
Answer: not a solution
Step-by-step explanation: 7a = 7 * 21 which does not equal 28, it equals 147, 7 * 4= 28, so actually a=4
Hope this helps :)
