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myrzilka [38]
3 years ago
9

Find the area of the triangle with 4 = 42º. b = 3 feet, and c= 5 feet. Round to the nearest tenth.​

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

Area = 5 sq ft

Step-by-step explanation:

Area of a Triangle with Side angle side method is given by the formula given as under

\ Area=\frac{bc \sin A}{2}

In our problem we are given that

A= 42◦

\sin 42=0.6691

b=3 \ feet

c=5 \ feet

Putting these values in the formula we get

\ Area=\frac{3 \times 5 \sin 42}{2}

\ Area=\frac{15 \times 0.6691}{2}

\Area=5.01

Hence Area of the Triangle is 5 Sq Ft

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The graph highlights two other points on the trend line. Use them to find another equation for the trend line shown for this sca
frutty [35]

Option A:

The equation for the trend line is y = 82x + 998.

Solution:

The points on the line are (2, 1162) and (11, 1900).

Here, x_1=2, y_1=1162, x_2 = 11, y_2=1900

Slope of the line:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

$m=\frac{1900-1162}{11-2}

$m=\frac{738}{9}

m = 82

Point-slope formula:

y-y_{1}=m\left(x-x_{1}\right)

y-1162=82\left(x-2\right)

y-1162=82x-164

Add 1162 on both sides of the equation.

y=82x+998

The equation for the trend line is y = 82x + 998.

Hence Option A is the correct answer.

4 0
3 years ago
Question Below And Please Answer ASAP!!
yuradex [85]
C is your answer

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6 0
3 years ago
Add a construction job for a gallery, 105 painters were tasked with painting the interior. These painters made up 75% of the tot
nexus9112 [7]
Let P stand for the Paint crew...and you know that 75% of that crew = 105 people. So we know that...
P x .75 = 105
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So the total paint crew has 140 painters.
7 0
3 years ago
Jenny wants to rent a truck for one day. She contacted two companies. Laguna’s Truck Rentals charges $20 plus $2 per mile. Salva
PolarNik [594]
20+2x=3x subtract 2x from both sides
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PROOF
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3 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
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