What is the equation of the line that contains point(3, -2) and has a slope of 5?
2 answers:
Answer:
y = 5x - 17
Step-by-step explanation:
y = mx + c
m = the gradient/slope = 5
y = 5x + c
Substitute (3, -2) into the equation above to find c.
-2 = 5(3) + c
-2 = 15 + c
-2 - 15 = c
-17 = c
y = 5x - 17
Answer:
Step-by-step explanation:
point(3, -2) and has a slope of 5
Slope m = 5
y1 = -2 and x1 = 3
The equation is
y - y1 = m(x - x1)
y + 2 = 5(x - 3)
y + 2 = 5x - 15
y = 5x - 15 - 2
y = 5x - 17
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