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DiKsa [7]
3 years ago
15

What is the equation of the line that contains point(3, -2) and has a slope of 5?

Mathematics
2 answers:
Olenka [21]3 years ago
5 0

Answer:

y = 5x - 17

Step-by-step explanation:

y = mx + c

m = the gradient/slope = 5

y = 5x + c

Substitute (3, -2) into the equation above to find c.

-2 = 5(3) + c

-2 = 15 + c

-2 - 15 = c

-17 = c

y = 5x - 17

tino4ka555 [31]3 years ago
5 0

Answer:

Step-by-step explanation:

point(3, -2) and has a slope of 5

Slope m = 5

y1 = -2 and x1 = 3

The equation is

y - y1 = m(x - x1)

y + 2 = 5(x - 3)

y + 2 = 5x - 15

y = 5x - 15 - 2

y = 5x - 17

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Show that there is no solution for the radical equation 4w+4=-4.
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Answer:

there is a solution

w= -2

Step-by-step explanation:

4w+4=-4

    -4    -4

4w=-8

/4    /4

w=-2

3 0
3 years ago
The length, l, of a rectangle is 3 times its width. The perimeter of the rectangle is greater than 48 centimeters. Which inequal
lana [24]
L>18
18/3 = 6
6(2) + 18(2) = 48
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3 years ago
0.44 in scientific notation
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44x10^-2
or in other words
44 times 10 to the -2nd power
3 0
4 years ago
6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the
MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

a_1 the horizontal distance between the first observer and the ballonist

a_2 the horizontal distance between the second observer and the ballonist

\alpha _1 and \alpha _2 the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

And for S_2 will be the same:

S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

So, we can replace all the known data in the last equation:

h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0
3 years ago
C=6x-4y solve equation
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You can solve any further
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