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DaniilM [7]
3 years ago
13

Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution?

Mathematics
2 answers:
ElenaW [278]3 years ago
6 0
The answer would be C
NeX [460]3 years ago
6 0
Hi! Whenever you are asked to find the solution to a system of equations using graphing, you should look for the point of interception. First, graph the two lines given using slope intercept form.

Slope intercept form: the number by the x is the slope, and the number standing along is the y-intercept.

After you graphed the two lines, look for the point where they meet. For example, in this problem it would be (-2,3).


And you’re done! The answer to this problem is C. I hope I helped you!! :))

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What is the answer to the equation: 7x + 4x +2​
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(7x + 4x) + 2

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3 years ago
The​ half-life of a certain tranquilizer in the bloodstream is 22 hours. How long will it take for the drug to decay to 90​% of
nasty-shy [4]

Answer:

It will take approximately 3.34 hours for the drug to decay to 90% of the original dosage

Step-by-step explanation:

As suggested, we use the formula for exponential decay:

A(t)=A_0\,e^{-k\,t}

From the given information, the half life of the drug in blood id 22 hours, so that means that it takes that number of hours to go from the initial value A_0, to a final value equal to A_0/2. Using this information we can find the decay rate "k" by solving for this parameter in the formula, and using the natural log function to bring the exponent down:

A(t)=A_0\,e^{-k\,t}\\\frac{A_0}{2} =A_0\,e^{-k\,*22}\\\frac{A_0}{A_0*2} =e^{-k\,*22}\\\frac{1}{2} =e^{-k\,*22}\\ln(\frac{1}{2})=-k\,*22\\ k=-\frac{ln(\frac{1}{2})}{22} \\k=0.0315

Now we use this value for the decay rate "k" to calculate how long it would take to decay to 90% of the original dose;

A(t)=A_0\,e^{-0.0315\,t}\\0.9*A_0} =A_0\,e^{-0.0315\,t}\\\frac{0.9*A_0}{A_0} =e^{-0.0315\,t}\\0.9 =e^{-0.0315\,t}\\ln(0.9)=-0.0315\,t\\ t=-\frac{ln(0.9)}{0.0315} \\t=3.3447\,hours

7 0
3 years ago
Please answer the question. The picture is right below.
zhenek [66]
Hey man I’ve never seen nothing like this but I’d you’re doing math on ap classroom , man , GOOD LUCK
5 0
3 years ago
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