The given equation is ⇒⇒⇒ 2y - 4x = 6
∴ 2y = 4x + 6 ⇒ divide all the equation over 2
∴ y = 2x + 3 and it can be written as ⇒⇒⇒ y - 2x = 3
The last equation represents a straight line with a slope = 2 and y-intercept = 3
To construct a system of equations with definitely many solutions and the equation ( 2y-4x=6 ) is one of the equations, the other equation must have the same slope and the same y-intercept.
so, the general solution of the other equation is ⇒ a ( y - 2x ) = 3a
Where a is constant and belongs to R ( All real numbers )
The system of equations which has definitely many solutions is consisting of <u>Coincident lines.</u>
For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
so 21 - 13, the money will be invested for 8 years.
9514 1404 393
Answer:
-0.16
Step-by-step explanation:
The 'a' value can be found by looking at the difference between the y-value of a point 1 unit from the vertex, and the y-value of the vertex.
Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...
y = a(x +2)^2 +4
Using the point (3, 0), we have ...
0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y
-4 = 25a . . . . . . . . . . subtract 4; next, divide by 25
a = -4/25 = -0.16
