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navik [9.2K]
3 years ago
7

BRAINLIEST!

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0
Assume that 7 is a. We already know that c = 25. The equation is c^2 - a^2 = b^2.
25^2= 625 7^2= 49 625-49= 576
Square root of 576 = 24

The length of thee other leg is 24.

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Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans
zloy xaker [14]
Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.



Part B:

The area of the square is given by

Area=(x+4)^2=x^2+8x+16

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

x^2+8x+16=6x+8 \\  \\ \Rightarrow x^2+8x-6x+16-8=0 \\  \\ \Rightarrow x^2+2x+8=0 \\  \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2}  \\  \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2}  \\  \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
7 0
3 years ago
Samuel is offering a pair of boots with an original price of $80.Store A is offering a 25% discount off the original price of al
oksian1 [2.3K]
B. Samuel will pay will 10 dollars less if he buys the boots from store A.
5 0
2 years ago
Solve the system of equations 2r + 2s = 50 and 2r – s = 17.
WARRIOR [948]
Eq1) 2r+2s=50
eq2) 2r-s=17

solve for s in equation2 (eq2)

-s=17-2r
s=-17+2r
Substitute s into equation1 (eq1)
2r+2(-17+2r)=50
2r-34+4r=50
6r-34=50
6r=50+34
6r=84
r=14
Substitute into either equation and solve for s
2(14)-s=17
28-s=17
-s=17-28
-s=-11
s=11
6 0
3 years ago
Find the value of each determinant
Ksenya-84 [330]

Answer:

−4304

Step-by-step explanation:

1. The given determinant is :

\begin{vmatrix}7 &31 \\  142& 14\end{vmatrix}

We need to find its determinant . It can be solved as follows :

\begin{vmatrix}7 &31 \\  142& 14\end{vmatrix}=7(14)-142(31)\\\\=-4304

So, the value of determinant is equal to −4304.

6 0
2 years ago
Find the percent markup
Aleks [24]
The final sale price would be $662.35
3 0
2 years ago
Read 2 more answers
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