2 classes of 21 students each
21 × 2 classes = 42 students in total
42 × 3 mins = 126 minutes for 42 students
10 mins for 2 class pics = 20 minutes
126 + 20 = 146 minutes = 2 hours and 26 minutes
It should take 146 minutes (2 hours and 26 minutes) to take all the pictures.
Answer:
The area of the polygon is 42
.
Step-by-step explanation:
A polygon is a shape that has three or more sides. They are named with respect to the number of their sides. Example, an octagon has 8 sides, hexagon has 6 sides etc.
From the given figure, the area of the shaded polygon can be calculated by;
Area of polygon = Area of square - Sum of areas given
Sum of areas given = 24 + 30 + 48
= 102
The four sides of the figure are equal, thus it is a square. The length of each side is 12 cm, so that:
Area of square = length × width
= 12 × 12
= 144
Area of polygon = 144 - 102
= 42
The area of the polygon is 42
.
First add up the total parts in the ratio.
5 + 4 = 9
Now we need to know the value of each part
36 / 9 = 4
The girls has total of 4 parts, therefore we can just multiply the number of parts by the amount in each part
4 x 4 = 16
So there r 16 girls in the class
Answer:
So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.
Absorbance is the inverse of transmittance so,
A = 1/T
Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:
A ∝ b · c
As Transmittance, 
% Transmittance, 
Absorbance,
Hence,
is the algebraic relation between absorbance and transmittance.
Complete Question:
The complete question is shown on the first uploaded image
Answer:
The probability that the random you randomly select species that are greater than 200 kg is = 7/62
Step-by-step explanation:
Step One: Load the data set in to the R work space
data(mammals,package="MASS")
attach(mammals)
Step 2 : Obtain the list of the species that are greater than 200 and store it on y variable.
y <- subset(mammals,body>200)
Step Three : Obtain the total size
nrow(mammals)
Step Four : Obtain the sum of species greater than 200
sum(body > 200)
total size = 62
size with body > 200 = 7
hence
required probability = 7/62