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nikklg [1K]
3 years ago
14

What is the sum of 667 and 23? A. 29 B. 690 C. 644 D. 15,341

Mathematics
2 answers:
butalik [34]3 years ago
5 0
If you would like to know what is the sum of 667 and 23, you can calculate this using the following steps:

the sum of 667 and 23:
667 + 23 = 690

The correct result would be B. 690.
mina [271]3 years ago
4 0
667+23={\boxed{690}

\sf\ ANSWER: B
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25 POINTS AVAILABLE
myrzilka [38]

Answer:

\large\boxed{1.\ (-3, 0),\ r = 3}\\\boxed{2.\ (x+4)^2+(y-3)^2=36}\\\boxed{3.\ (x-2)^2+(y-1)^2=(\sqrt{34})^2}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

1. We have the equation:

(x+3)^2+y^2=9\\\\(x-(-3))^2+(y-0)^2=3^2

<h2 />

2. We have the center (-4, 3) and the radius r = 6. Substitute:

(x-(-4))^2+(y-3)^2=6^2\\\\(x+4)^2+(y-3)^2=36

3. We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

7 0
3 years ago
What is the approximate circumference of the circle that has a center at (2, 1) and passes through the point (7, 1)? A 10 units
Naddik [55]

Answer:

C. 31 units

Step-by-step explanation:

Circumference of a circle is the distance around the circle and is given by C = pi•d

Your circle with a point and center given has a radius of 5 because from (2,1) to (7,1) is 5 units. Radius 5 means the diameter is 10.

C = pi•10

= 3.14•10

= 31.4 using 3.14 as an approximation for pi.

Circumference is approximately 31 units.

5 0
2 years ago
Read 2 more answers
a fishing tackle box is 13 inches long 6 inches wide and 2 1/2 inches high. what is the volume of the tackle box
grandymaker [24]

Answer:

195 cubic inches

Step-by-step explanation:

A fishing tackle box is 13 inches long, 6 inches wide, and inches high. What is the volume of the tackle box? SOLUTION: The volume of the tackle box is 195 cubic inches.

7 0
2 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
2 years ago
Please help me this is my last question!!!no scammers plz i got scammed 5 times now
MAVERICK [17]

Answer:

A)  5600 ft

B)   5600 ft

C0 More than a mile

Step-by-step explanation:

4850 * sin(60) = 5600

4 0
2 years ago
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