2 1/2 .need 20 characters to post
Step-by-step explanation:


Answer:
Step-by-step explanation:
a = 20(hypotenuse)
b = 12(leg)
z = ?
z=
= 16
Answer:
Step-by-step explanation:
B
2
3
Let the distance of two consecutive stones are x, x+1.
In ΔBCD, we have
tan60
o
=
x
h
⇒x=
3
h
.....(i)
In ΔABC, we have
tan30
o
=
x+1
h
⇒
3
1
=
x+1
h
⇒
3
h
+1=
3
h ......[from equation (i)]
⇒
3
2h
=1
⇒h=
2
3
km
solution