All categories

2 years ago

Can someone pls help i need your help

Mathematics

2 answers:

Anna35 [415]2 years ago

8 0

12 miles
hope this is helpful!

WITCHER [35]2 years ago

8 0

Answer:

12 miles

Step-by-step explanation:

You would have to divide $26.40 by $2.20 which equals 12 so she traveled 12 miles.

You might be interested in

Wht are the next three terms in the sequence -3 6 15 24

kogti [31]

6--3=9
15-6=9,
so
24+9=33,
33+9=42,
42+9=51
33,42,51

4 0

3 years ago

Read 2 more answers

70% in the SIMPLEST Form

masya89 [10]

Answer:

7/100

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

GCD of 70 and 100 is 10

Divide both the numerator and denominator by the GCD

70 ÷ 10

100 ÷ 10

Reduced fraction:

Therefore, 70/100 simplified to lowest terms is 7/10.

4 0

3 years ago

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26

guajiro [1.7K]

We have

SinC/ c = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A = 27 Sin 71 / 26 = about .982

So°

Sin-1(.982) = A = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

b/sin29.92 = 26/sin 71

b = 26sin29.92/sin71 = about 13.72

But A could also be an obtuse angle = 180 - 79.08 = 100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08 = 26/sin71

b = 26sin8.08/sin 71 = 3.865

8 0

3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0

2 years ago

Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at le

kumpel [21]

<span>Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at least one of each color is drawn.</span>

5 0

3 years ago