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Advocard [28]
3 years ago
14

Consider the graph of the linear equation 2x-5y=10. What is the x-intercept? What is the y-intercept? What is the slope?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
Hey there!

This linear equation is written in standard form, a form in which it's quite easy to find intercepts for one main reason. This reason revolves around zeros. When you see an x intercept, there's always a zero for the y, and when there's a y you see a zero for the x. Therefore, we can do this to get the intercepts.

For x:

2x-5(0) =10
2x = 10
x = (5,0)

For y:

2(0) -5y = 10
-5y=10
y= (0,-2)

Now, to find the slope, we can easily convert it to slope intercept form:

y = mx+b

Where m is the slope and b is he y intercept.

2x-5y=10
-5y=-2x+10
y = 2/5x-2
(notice how we divided both sides by -5)

Therefore, our slope is 2/5. Hope this helps!
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Find all numbers whose absolute value is -9.
Neko [114]

Answer:

None

Step-by-step explanation:

A number's absolute value will always be positive

|9| = 9

|-9| = 9

3 0
3 years ago
Read 2 more answers
Someone please help me I’ll give out brainliest please dont answer if you don’t know
natta225 [31]

Answer:

12.5(x  + 20) = 460 \\ x + 20 = 460 \div 12.5 \\ x + 20 = 36.8 \\ x = 36.8 - 20 \\ x = 16.8

Hence, 16.8 miles is your answer

3 0
3 years ago
When y=7.5 x=2 what is the value of y when x is 2 1/4
swat32
<h2>Answer:</h2>

The value of y is 8.4375

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • y = 7.5
  • x = 2

<h3>Asked :</h3>
  • The value of y when x is 2.25

<h3>Solution :</h3>

2/7.5 = 2.25/y

Do a cross multiplication,

2/7.5 = 2.25/y

=> 20/75 = 2.25/y

=> 75 . 2.25 = 20y

=> 168.75 = 20y

Reverse the equation,

168.75 = 20y

=> 20y = 168.75

Find the value of y,

20y = 168.75

=> y = 8.4375

<h3>Conclusion :</h3>

y = 8.4375

7 0
2 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
An object that starts at rest accelerates until it is moving at 247 km/h. If it takes 1.7 minutes for this change to occur what
fredd [130]

I figured out the answer Chaseashley24! The answer to your question is:

0.673 m/s²

Hope this helps!

6 0
3 years ago
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