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Advocard [28]
3 years ago
14

Consider the graph of the linear equation 2x-5y=10. What is the x-intercept? What is the y-intercept? What is the slope?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
Hey there!

This linear equation is written in standard form, a form in which it's quite easy to find intercepts for one main reason. This reason revolves around zeros. When you see an x intercept, there's always a zero for the y, and when there's a y you see a zero for the x. Therefore, we can do this to get the intercepts.

For x:

2x-5(0) =10
2x = 10
x = (5,0)

For y:

2(0) -5y = 10
-5y=10
y= (0,-2)

Now, to find the slope, we can easily convert it to slope intercept form:

y = mx+b

Where m is the slope and b is he y intercept.

2x-5y=10
-5y=-2x+10
y = 2/5x-2
(notice how we divided both sides by -5)

Therefore, our slope is 2/5. Hope this helps!
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Step-by-step explanation:

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Here hope this helps best of luck :)




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While constructing an equilateral triangle or a regular hexagon inscribed in a circle, you may have noticed that several smaller
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Answer:

Using the transitive property of geometry, we proved that △PQR is an equilateral triangle.

Step-by-step explanation:

The diagram of the given scenario is in the attachment.

Here, PQ is the radius of circle Q

Also, PQ is the radius of circle P

Hence, circle-P and circle-Q have same radii.

Now, PQ=RQ as both are radii of circle Q

And PQ=PR, as both are radii of circle P

Hence as per transitive property, which states that, if any two angles, lines, or shapes are congruent to a third angle, line, or shape respectively, then the first two angles, lines, or shapes are also congruent to the third angle, line, or shape

PR=QR

Now, PQ = QR = PR

Hence, ∆PQR is equilateral.

For more explanation, refer the following link:

brainly.com/question/27884420

#SPJ10

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(-3,8) would NOT fit the table.

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