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ankoles [38]
3 years ago
5

Find the area and perimeter please help me :)

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

Perimeter: 44

Area: 96

Step-by-step explanation:

Perimeter - Just add all the sides together, 4 + 10 + 12 +7 + 8 + 3.

(The 8 and the 3 are apart of the sides that are not labeled. Since 12 - 4 = 8, and 10 - 7 = 3, That's where these numbers come from.)

Area - 4 * 10 = 40,

 +        8 * 7 =  56,

--------------------------------

                   = 96

I hope this helps :)

avanturin [10]3 years ago
7 0

Answer:

Perimeter is 44cm

Area is 96cm²

Step-by-step explanation:

Perimeter=side+ side+side.....

●To find the missing horizontal side use the sides they give you :.the horizontal side will be 12-4 =8

●Do the same to find the missing vertical side:

10-7=3

:. Perimeter= 4+10+12+7+8+3

=44

(If you were to skip steps you could've also just seen it as 10+12+10+12=44)

To find area break the shape into manageable shapes you know the area formula of, like 2 rectangles. To help visualize it draw a line separating down from the 3cm vertical side we just calculated.

Area of rectangle 1 = length x breadth

=4×10

=40 units²

Area of rectangle 2 =length x breadth

=7×8

=56 units²

Therefore total area= rectangle 1 + rectangle 2

= 40 units²+ 56 units²

= 96 units²

Tip...to help when calculating do'nt be afraid to draw on the diagram and fill in the numbers you calculated previously to prevent confusion.

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The sum of two numbers is 1. If one number is subtracted from the other, their difference is - 17. Find the numbers.
Maksim231197 [3]

Answer:

-17(-)-18=-17+18=1 or -17+18=1

Step-by-step explanation:

if -17 is one number you Add 18.

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3 years ago
Given the functions f(x) = x + 4 and g(x) = x2 − x find the value of each expression below.
dexar [7]

f(x) = x + 4

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7 0
3 years ago
A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F
Dima020 [189]

Answer:

(a) The probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b) The probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c) The probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

Step-by-step explanation:

The complete question is:

A really bad carton of 18 eggs contains 8 spoiled eggs. An unsuspecting chef picks 5 eggs at random for his “Mega-Omelet Surprise.” Find the probability that the number of unspoiled eggs among the 5 selected is

(a) exactly 5

(b) 2 or fewer

(c) more than 1.

Let <em>X</em> = number of unspoiled eggs in the bad carton of eggs.

Of the 18 eggs in the bad carton of eggs, 8 were spoiled eggs.

The probability of selecting an unspoiled egg is:

P(X)=p=\frac{10}{18}=0.556

A randomly selected egg is unspoiled or not is independent of the others.

It is provided that a chef picks 5 eggs at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.556.

The success is defined as the selection of an unspoiled egg.

The probability mass function of <em>X</em> is given by:

P(X=x)={5\choose x}(0.556)^{x}(1-0.556)^{5-x};\ x=0,1,2,3...

(a)

Compute the probability that of the 5 eggs selected exactly 5 are unspoiled as follows:

P(X=5)={5\choose 5}(0.556)^{5}(1-0.556)^{5-5}\\=1\times 0.05313\times 1\\=0.0531

Thus, the probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b)

Compute the probability that of the 5 eggs selected 2 or less are unspoiled as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

              =\sum\imits^{2}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=0.0173+0.1080+0.2706\\=0.3959

Thus, the probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c)

Compute the probability that of the 5 eggs selected more than 1 are unspoiled as follows:

P (X > 1) = 1 - P (X ≤ 1)

              = 1 - P (X = 0) - P (X = 1)

              =1-\sum\limits^{1}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=1-0.0173-0.1080\\=0.8747

Thus, the probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

6 0
3 years ago
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