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Luba_88 [7]
3 years ago
10

Find the buying price of each of the following when 5% sales tax is added on the purchase of;

Mathematics
2 answers:
atroni [7]3 years ago
7 0
1. 60 + 60*0.05 = 60 + 3 = 63;
2. 50 + 50*0.05 = 50 + 2.5 = 52.5;

mylen [45]3 years ago
3 0

just want someone to talk to

plz don't report me

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EVERYONE, PLEASE HELP I NEED THIS DONE
zimovet [89]

Answer:

\frac{4}{5}

Step-by-step explanation:

\frac{32}{40}

Both 32 and 40 are divisible by 8.
32÷8=4

40÷8=5

Thus, the simplest form is \frac{4}{5}

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ten people put there name into two different drawings. The first drawing is a trip to hawaii and the second is a new car. what i
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unlikely

Step-by-step explanation:

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3 years ago
A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0
3 years ago
GIVING 50 POINTS TO WHOEVER ANSWERS CORRECTLY!!!!!!
mars1129 [50]

Answer:

(2,-2) --> (-1, 3)

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(8,-5) --> (5, 0)

(2,-5) --> (-1, 0)

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2 years ago
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Yakvenalex [24]
\bf \begin{array}{llll}&#10;-5x-y=5\\&#10;-5x+y=5\\&#10;-------\\&#10;-10x+0=10&#10;\end{array}\implies -10x=10\implies x=-1

so if x = -1, let's plug that in the second equation

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