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Luba_88 [7]
3 years ago
10

Find the buying price of each of the following when 5% sales tax is added on the purchase of;

Mathematics
2 answers:
atroni [7]3 years ago
7 0
1. 60 + 60*0.05 = 60 + 3 = 63;
2. 50 + 50*0.05 = 50 + 2.5 = 52.5;

mylen [45]3 years ago
3 0

just want someone to talk to

plz don't report me

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Does 7.5 quarts =1 pint
Nataly_w [17]
No there are two pints in a quart
6 0
3 years ago
Read 2 more answers
What is the completely factored form of f(x)=x^3-7x^2+2x+4
xxMikexx [17]

Solution, \mathrm{Factor}\:x^3-7x^2+2x+4:\quad \left(x-1\right)\left(x^2-6x-4\right)

Steps:

x^3-7x^2+2x+4

Use\:the\:rational\:root\:theorem,\\a_0=4,\:\quad a_n=1,\\\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:4,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\\\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:4}{1},\\\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x-1,\\\left(x-1\right)\frac{x^3-7x^2+2x+4}{x-1}

\frac{x^3-7x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{x^3-7x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^3-7x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{x^3}{x},\\\mathrm{Quotient}=x^2,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}x^2:\:x^3-x^2,\\\mathrm{Subtract\:}x^3-x^2\mathrm{\:from\:}x^3-7x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-6x^2+2x+4,\\Therefore,\\\frac{x^3-7x^2+2x+4}{x-1}=x^2+\frac{-6x^2+2x+4}{x-1}

\mathrm{Divide}\:\frac{-6x^2+2x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-6x^2+2x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-6x^2}{x}=-6x,\\\mathrm{Quotient}=-6x,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-6x:\:-6x^2+6x,\\\mathrm{Subtract\:}-6x^2+6x\mathrm{\:from\:}-6x^2+2x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=-4x+4,\\\mathrm{Therefore},\\\frac{-6x^2+2x+4}{x-1}=-6x+\frac{-4x+4}{x-1}

\mathrm{Divide}\:\frac{-4x+4}{x-1},\\\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}-4x+4\mathrm{\:and\:the\:divisor\:}x-1\mathrm{\::\:}\frac{-4x}{x}=-4,\\\mathrm{Quotient}=-4,\\\mathrm{Multiply\:}x-1\mathrm{\:by\:}-4:\:-4x+4,\\\mathrm{Subtract\:}-4x+4\mathrm{\:from\:}-4x+4\mathrm{\:to\:get\:new\:remainder},\\\mathrm{Remainder}=0,\\\mathrm{Therefore},\\\frac{-4x+4}{x-1}=-4

\mathrm{The\:Correct\:Answer\:is\:\left(x-1\right)\left(x^2-6x-4\right)}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

8 0
3 years ago
Simplify h^6 x h ASAP please
ozzi

Answer:1/2

Step-by-step explanation:

8 0
3 years ago
Dani has only 1/2 of a cup of baking mix. She needs 3/4 of a cup for one batch of muffins. Which solution method shows how much
Vilka [71]

Answer:

Step-by-step explanation:

Dani has only 1/2 of a cup of baking mix. She needs 3/4 of a cup for one batch of muffins. Which solution method shows how much of a batch of muffins Dani can make?

3 0
3 years ago
We wish to estimate what percent of adult residents in a certain county are parents. Out of 500 adult residents sampled, 175 had
shepuryov [24]

Answer:

The 99% confidence interval  is  0.3003  < I  <  0.3997

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  500

      The the number that are parents  x =  175

The  proportion of parents is  mathematically represented as

       \r p  =  \frac{x}{n}

substituting values

      \r  p  =  \frac{175}{500}

     \r  p  = 0.35

The  level of confidence is given as 99%  which implies that the level of significance is  

       \alpha  = 100 - 99

       \alpha =1%

      \alpha  = 0.01

The critical value for this level of significance is obtained from the table of critical value as

          t_{x, \alpha } =  t_{175, 0.05}  =  2.33

Generally the margin of error is mathematically evaluated as

       M  =\frac{ t_{175, 0.01 } *  \sqrt{\r p (1-\r p)} }{\sqrt{n} }

substituting values

     M  =\frac{ 2.33 *  \sqrt{\r 0.35 (1-0.35)} }{\sqrt{500} }

     M  = 0.0497

Generally the 99% confidence interval is mathematically represented as

        I  = \r p \pm  M

    \r  p -M  < I  <  \r p + M

substituting values

    0.35 -0.0497  < I  <   0.35 + 0.0497

    0.3003  < I  <  0.3997

5 0
3 years ago
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