Answer:
Step-by-step explanation:
Given that there are 3 sets such that there are 100 elements in A1, 1000 in A2, and 10,000 in A3
a) If A1 ⊆ A2 and A2 ⊆ A3
then union will contain the same number of elements as that of A3
i.e. 
b) If the sets are pairwise disjoint.
union will contain the sum of elements of each set

c) If there are two elements common to each pair of sets and one element in all three sets
We subtract common elements pairwise and add common element in 3
i.e. 
Complete question :
According to the National Beer Wholesalers Association, U.S. consumers 21 years and older consumed 26.9 gallons of beer and cider per person during 2017. A distributor in Milwaukee believes that beer and cider consumption are higher in that city. A sample of consumers 21 years and older in Milwaukee will be taken, and the sample mean 2017 beer and cider consumption will be used to test the following null and alternative hypotheses:
H, :μ< 26.9
Ha : μ> 26.9
a. Assume the sample data led to rejection of the null hypothesis. What would be your conclusion about consumption of beer and cider in Milwaukee?
b. What is the Type I error in this situation? What are the consequences of making this error?
c. What is the Type II error in this situation? What are the consequences of making this error?
Answer:
Kindly check explanation
Step-by-step explanation:
Given the null and alternative hypothesis :
H0 :μ< 26.9
Ha : μ> 26.9
Assume the Null hypothesis is rejected ;
We conclude that there is significant evidence that the mean consumption of beer and cider is higher in the city (more than 26.9 gallons).
B.) Type 1 error is committed when the Null hypothesis is incorrectly rejected.
C.) Type 2 error is committed when we fail to reject a false null hypothesis. In this scenario, we fail to conclude that the average consumption of beer and cider is more than 26.9 gallons per person.
1) To write 0.259 as a fraction let's firstly rewrite as

2) Count the digits the dot has gone to the left. Each digit to the left means divided by ten. Like this:
3) Since it starts with a zero then it can't be a Mixed number. So it is an improper fraction. No further simplification could be done.