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Brilliant_brown [7]
3 years ago
11

The Function approximate the velocity (in feet per second) of an object dropped from a height of x feet

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

The answer to the question is

It take for the golf ball hit on Mars to reach the ground 8.284 s longer.

Step-by-step explanation:

To Solve the question, we note that the equation of motion is given to us as

h = -1.9·t² + 26·t

Therefore the height

We compare the above equation with the equation of of motion

S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and  - 0.5×g = -1.9

Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²

We now have the time taken to maximum height given by

v = u - g·t where v = 0 at maximum height

We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds

The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s

The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.

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Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
2 years ago
What is the volume of the right rectangular prism?
ddd [48]

Answer:

i think its 735

Step-by-step explanation:

since the base is a square it should be a whole square which is 7 and the height is 15 and v=whl and multiply all of it 7 times 7 is 49 times 15 is 735.

5 0
3 years ago
3475 milliliters to liters
kirill115 [55]
3.475
hope this helps!!
3 0
3 years ago
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Find the value of x.
Artemon [7]
I believe it is 83 because a straight line is 180 degrees
6 0
3 years ago
The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?
Arturiano [62]

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole =\frac{1}{3} \pi r^2 h

So, Volume of conical hole =\frac{1}{3} \pi \times r^2 \times 9

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So,\frac{1}{3} \pi \times r^2 \times 9=75 \pi

\frac{1}{3} \times r^2 \times 9=75

r^2=\frac{75 \times 3}{9}

r=\sqrt{\frac{75 \times 3}{9}}

r=5

Hence The radius of hole is 5 feet

6 0
3 years ago
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