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Brilliant_brown [7]
3 years ago
11

The Function approximate the velocity (in feet per second) of an object dropped from a height of x feet

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

The answer to the question is

It take for the golf ball hit on Mars to reach the ground 8.284 s longer.

Step-by-step explanation:

To Solve the question, we note that the equation of motion is given to us as

h = -1.9·t² + 26·t

Therefore the height

We compare the above equation with the equation of of motion

S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and  - 0.5×g = -1.9

Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²

We now have the time taken to maximum height given by

v = u - g·t where v = 0 at maximum height

We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds

The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s

The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.

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galina1969 [7]
Ok so all you have to do is multiple 9 And 4 ok then you will get you answer





Hope this helps





Don't forget to rate and thanks me
4 0
3 years ago
Read 2 more answers
PLEASE HELP!! 30 POINTS
AveGali [126]
The answer is b if you add 3 plus -5 that would have given you negative -2
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3 years ago
I need help is due in 20 minute
AfilCa [17]
A is 5 , b is 1 , c is 4 , d is 3, and E is 2
7 0
3 years ago
Fill in the missing value to make the equations true.
Furkat [3]

Answer:

a) 7/4 b) 5 c) 2

Step-by-step explanation:

Logrithmic Rule for a and b

Let a, M, N be positive real numbers.

a)  

logaM - logaN = loga(M/N)

log9(7) - log9(4) = log9 (7/4)

b)

logaM + logaN = logaMN

log2 (x) + log2(9) = log2(45)

x9=45

(x9)/9 = 45/9

x = 5

c)

Change of base formula.

logb​(x)=logd​(b)/logd​(x)​

x log6(5) = log6(25) divide each term by log6(5)

x log6(5) / log6(5) = log6(25) / log6(5)   Cancel common factor log6(5)

x = log6(25) / log6(5)

x = log6(5^2) / log6(5)

Expand log6(5^2) by moving 2 outside the logarithm.

x = 2log6(5) / log6(5) cancel the like term log6(5)

x = 2

7 0
3 years ago
Find the general solution for the differential equation (dy)/(dx) + 3y = 18<br> Y=
harkovskaia [24]

Answer:

y=-e^{-3x-c_1}+6

Step-by-step explanation:

\frac{dy}{dx}+3y=18\\\\\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:\\\\y'\:+3y=18\\\\Rewrite\\\\\frac{1}{6-y}y'\:=3\\\\Solve \::\frac{1}{6-y}y'\:=3\\\\-In(6-y)=3x+c_1\\\\Isolate\:y\\\\\\y=-e^{-3x-c_1}+6

5 0
3 years ago
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