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Brilliant_brown [7]
3 years ago
11

The Function approximate the velocity (in feet per second) of an object dropped from a height of x feet

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

The answer to the question is

It take for the golf ball hit on Mars to reach the ground 8.284 s longer.

Step-by-step explanation:

To Solve the question, we note that the equation of motion is given to us as

h = -1.9·t² + 26·t

Therefore the height

We compare the above equation with the equation of of motion

S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and  - 0.5×g = -1.9

Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²

We now have the time taken to maximum height given by

v = u - g·t where v = 0 at maximum height

We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds

The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s

The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.

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arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
Enter the equations of the asymptotes for the function f(x).<br><br> f(x)= 3/x−7 + 2
Alexxx [7]

Answer:

x = 7, y = 2

Step-by-step explanation:

I assume it is 3/(x-7) + 2.

When x = 7, there is an asymptote because it is undefined.

When y = 2, there is also one, because 3/(x-7) is never 0.

These are the only ones.

3 0
3 years ago
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Vadim26 [7]
V = w * L * H  = 4 *2 *2  or 4*2^2

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5 0
3 years ago
The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6 minutes and the variance of
White raven [17]

Answer:

0.3075 = 30.75% probability that a person will wait for more than 7 minutes.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The standard deviation is the square root of the variance.

In this problem, we have that:

\mu = 6, \sigma = \sqrt{4} = 2

Find the probability that a person will wait for more than 7 minutes.

This is 1 subtracted by the pvalue of Z when X = 7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{7 - 6}{2}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

0.3075 = 30.75% probability that a person will wait for more than 7 minutes.

7 0
3 years ago
Find the estimate &amp; difference for 4-1.29
rewona [7]
Difference is 2.71 and the estimate is 3
4 0
3 years ago
Read 2 more answers
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