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Andrews [41]
3 years ago
7

Suppose that you randomly draw one card from a standard deck of 52 cards. After writing down which card was drawn, you replace t

he card, and draw another card. You repeat this process until you have drawn 19 cards in all. What is the probability of drawing at least 8 clubs? For the experiment above, let X denote the number of clubs that are drawn. For this random variable, find its expected value and standard deviation.
Mathematics
1 answer:
34kurt3 years ago
8 0

Answer:

The probability is 0.0775

The expected value is 4.75 clubs

The standard deviation is 1.8875 clubs

Step-by-step explanation:

The variable X follows a binomial distribution, because we have n identical and independent events (19 cards) with a probability p of success and 1-p of fail (there is a probability of 1/4 to be club and 3/4 to be diamond, heart or spade). Then, the probability that x of the n cards are club is:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\P(x)=\frac{19!}{x!(19-x)!}*0.25^{x}*(0.75)^{19-x}

So, the probability P of drawing at least 8 clubs is:

P = P(8) + P(9) + P(10) + ... + P(18) + P(19)

Replacing, the values of x, from 8 to 19, on the equation above, we get:

P = 0.0775

Additionally, the expected value E(x) and standard deviationS(x) for this distribution is given by:

E(x)=np = 19(0.25) = 4.75

S(x)=\sqrt{np(1-p)} =\sqrt{19(0.25)(0.75)} =1.8875

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