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Vedmedyk [2.9K]
3 years ago
12

Please Answer questions 29 thru 40 for me please it's due tommorow!!

Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0
29) >
30)>
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40) >
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Write the equation y=4x+9 in standard form using integers.
rosijanka [135]

Answer:

4x-y=-9

Step-by-step explanation:

The standard form of an equation is when both variables, x & y, are on the same side of the equation with a number on the other side.

To transform this equation from slope-intercept form to standard form, just switch sides for the y and the 9 like follows.

4x-y=-9

I hope this helped you :D

4 0
3 years ago
What is the value of x in the equation? 5 5/6 x + 2 2/3 = 12
devlian [24]

Answer:

The value of x is 8/5

Step-by-step explanation:

(35/6)x + (8/3) = 12

(35/6)x = 28/3 (cross multiplication)

105x = 168

x = 8/5

5 0
3 years ago
Peter answered 15 questions on a quiz and obtained 29 points. If 3 points were given for each correct answer and one point deduc
nalin [4]

Answer: peter got 11 right and 4 wrong

Step-by-step explanation: So when he answers 11 answers correctly he gains 33 points so he loses 4 points from the remaining 4 wrong answers.

8 0
3 years ago
The hyperbola with center at (0, 0) opening horizontally, with a = 2, b = 5.
Finger [1]
I dont know if this is what you are looking for but i think this is the answer of the question you are looking for which is the general equation of a horizontal hyperbola: 
<span>(x-h)²/a² - (y-k)²/b² = 1 </span>
<span>with </span>
<span>center (h,k) 
</span>What you need to do is replace the data and do the calculations
8 0
3 years ago
A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven
Cerrena [4.2K]

Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y)  = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$  .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$  .............(ii)

Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-<u>)     8x - 32y = -50   </u>

                        264x        = 450

∴   $x=\frac{450}{264}=\frac{75}{44}$

     $y=\frac{175}{88}$

So, x ≈  $ 1.70      and    y = $ 1.99

    R(1.70, 1.99) = $ 134.94

Thus, 1.70 dollars per cola

          1.99 dollars per iced ted to maximize the revenue.

Maximum revenue = $ 134.94

4 0
3 years ago
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