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Strike441 [17]
2 years ago
9

HELP ME PLEASE I BEG YOU I REALLY NEED WITH THESE QUESTIONS!!!!!!!! RUBE

Mathematics
1 answer:
pickupchik [31]2 years ago
8 0
The first question above number 4 is A the first one the answer for number/question 4 is B. and that last question is A. and B. im sure of it please let me know if im right
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Alinethatincludesthepoint(2, 7)has slope of 5 . what isitsequationin slope -intercept form
Vesna [10]
10? Im not sure though my friend just told me it was 10
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Determine if its possible to form a triangle using the set of segments with the given measurement. explain please! 12 m, 5 m, 18
IRINA_888 [86]

Adding together the shorter two sides results in 17 m.  If these two sides were laid end to end, the sum of their sides (17 m) would be less than the length of the third side.  Thus, NO triangle could be constructed with this set of line segments.

6 0
3 years ago
Help pls!!!!! Thankssss
prisoha [69]
I think the answer is C
4 0
3 years ago
Read 2 more answers
How to do graphs of quadratic functions ​
Anastaziya [24]

Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

4 0
2 years ago
Plz help
inn [45]
We are given with
P(pop quiz) = 60%
P(not do homework) = 85%

And the condition that
P (pop quiz and do homework) > 5%

So,
P (pop quiz) x P (do homework)
P (pop quiz) x ( 1 - P (not do homework) )
60% x ( 1 - 85%)

The result is greater than five percent so he will not do his homework.
5 0
3 years ago
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