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ratelena [41]
3 years ago
9

6th grade work please tell me the answer fast and don’t give me and incorrect one

Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0

Answer: 222cm

Step-by-step explanation:

To find the area of this composite shape you will have to split them into 2 shapes; a rectangle and a triangle.

To work out the area of the rectangle you have to do 15×12= 180

Then, to work out the area of the triangle, you use the formula base times height divided by 2.

7×12=84

84÷2=42

Then to work out the total area of both the rectangle and the triangle, you have to add the area of both.

180+42=222cm

Hope this helps :)

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2 years ago
Is 1/28 = 16 1/2? I’m just using extra word because it making me type more but please answer ASAP
masya89 [10]

Answer:

NO IT IS NOT

Step-by-step explanation:

16 1/2 = 16.5 1/28 = 0.0357

NOT THE SAME!!!!!

Please mark brainiest if this is helpful! :D

8 0
2 years ago
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Sarah is a computer engineer and manager and works for a software company. She receives a
daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = a

Given that:

a_4=129\\a_{10}=207

Formula for n^{th} term of an Arithmetic Progression is given as:

a_n=a+(n-1)d

Where d will represent the number of projects increased every year.

and n is the year number.

a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)

Subtracting (2) from (1):

78 = 6d\\\Rightarrow d =13

By equation (1):

129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233

Each project pays $500

Earnings in the twelfth year = 233 \times 500 = $116500

Sum of an AP is given as:

S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 \times 1938 = $969000

8 0
2 years ago
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lions [1.4K]

Answer:

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Step-by-step explanation:

12 times a number (represented by n) is 12n.

"Decreased by 5" means 5 is subtracted from the product, giving 12n-5.

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5/7 = x/42
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