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klasskru [66]
2 years ago
6

PLEASE HELP: Simplify the expression. Write your answer as a power. 5^2⋅5^9/5

Mathematics
1 answer:
antoniya [11.8K]2 years ago
7 0

Answer:

9.765625×10^6

Step-by-step explanation:

Simplify the following:

5^2×5^9/5

Hint: | Express 5^2×5^9/5 as a single fraction.

5^2×5^9/5 = (5^2×5^9)/5:

(5^2×5^9)/5

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to (5^2×5^9)/5.

Combine powers. (5^2×5^9)/5 = 5^(9 + 2 - 1):

5^(9 + 2 - 1)

Hint: | Evaluate 9 + 2.

9 + 2 = 11:

5^(11 - 1)

Hint: | Subtract 1 from 11.

| 1 | 1

- | | 1

| 1 | 0:

5^10

Hint: | Compute 5^10 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

5^10 = (5^5)^2 = (5×5^4)^2 = (5 (5^2)^2)^2:

(5 (5^2)^2)^2

Hint: | Evaluate 5^2.

5^2 = 25:

(5×25^2)^2

Hint: | Evaluate 25^2.

| 2 | 5

× | 2 | 5

1 | 2 | 5

5 | 0 | 0

6 | 2 | 5:

(5×625)^2

Hint: | Multiply 5 and 625 together.

5×625 = 3125:

3125^2

Hint: | Evaluate 3125^2.

| | | 3 | 1 | 2 | 5

× | | | 3 | 1 | 2 | 5

| | 1 | 5 | 6 | 2 | 5

| | 6 | 2 | 5 | 0 | 0

| 3 | 1 | 2 | 5 | 0 | 0

9 | 3 | 7 | 5 | 0 | 0 | 0

9 | 7 | 6 | 5 | 6 | 2 | 5:

Answer: | 9765625 = 9.765625×10^6

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Mr Nersin likes to ride his bike. He rode for 1/2 hour. After a short rest, he rode 1/10 hour more. He traveled 4 miles in all.
vodomira [7]
The distance traveled by Mr.Nersin = 4 miles
The time for which Mr.Nersin rode first = 1/2 hour
The time for which Mr.Nersin rode after a short rest = 1/10 hour
Then
The total time for which Mr.Nersin rode = (1/2) + (1/10) hour
                                                                = (5 + 1)/10 hour
                                                                = 6/10 hour
                                                                = 3/5 hour
So
Average speed of Mr. Nersin = Distance traveled / Time taken
                                                = 4/(3/5) miles/hour
                                                = (4 * 5)/3 miles/hour
                                               = 20/3 miles/hour
                                                = 6 2/3 miles/hour
                                                = 6.67 miles per hour
So the average speed at which Mr.Nersin traveled is 6 2/3 or 6.67 miles per hour.
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3 years ago
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The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and
a_sh-v [17]

Answer:

No, that is not possible

Explanation:

P = 2L + 2W

Insert numbers into equation

p=(2)(20)+(2)(11)

Step 1: Simplify both sides of the equation.

p=(2)(20)+(2)(11)

p=40+22

p=(40+22)(Combine Like Terms)

p=62

p=62

The perimeter is 62, not 64, so the perimeter can't be 64 if the length 20 and the width is 11.

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Step-by-step explanation:

At Bob's binders, the unit price = $4.20 ÷ 3

= $1.40

At Pam's Paper Place the unit price = $5.20 ÷ 4 = $1.30

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Find an equivalent system of equations for the following system: 3x + 3y = 0 −4x + 4y = −8 3x + 3y = 0 7x − y = 8 3x + 3y = 0 −7
Charra [1.4K]

Answer:

A.

3x + 3y = 0

7x − y = 8

Step-by-step explanation:

Given

3x + 3y = 0

-4x + 4y = -8

Required

Find the equivalent

To solve for the equivalent we simply solve for x and y in the given equation.

Subtract 3x from both sides in 3x + 3y = 0

3x - 3x + 3y = 0 - 3x

3y = -3x

Multiply both sides by ⅓

⅓ * 3y = -3x * ⅓

y = -x

Substitute -x for y in -4x + 4y = -8

-4x + 4(-x) = -8

-4x -4x = -8

-8x = -8

Multiply both sides by -⅛

-⅛ * -8x = -⅛ * -8

x = 1

Recall that y = -x

y = -1

So, we have that x = 1 and y = -1

We'll substitute these values in the list of options;

A.

3x + 3y = 0

7x − y = 8

7(1) - -(1) = 8

7 + 1 = 8 ----- This is equivalent

B.

3x + 3y = 0

−7x − y = 8

-7(1) - (-1) = 8

-7 + 1 = 8

-6 ≠ 8 .... This is not an equivalent expression

C.

3x + 3y = 0

−7x + 7y = 8

-7(1) + 7(-1) = 8

-7 -7 = 8

-14 ≠ 8 .... This is also not an equivalent expression

D.

3x + 3y = 0

-4x + 7y = 8

-4(1) + 7(-1) = 8

-4 -7 = 8

-11 ≠ 8 -_- This is also not an equivalent expression

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4 years ago
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