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ratelena [41]
3 years ago
8

Explain how a magnetic compass can be used to find directions on Earth’s surface

Physics
1 answer:
irakobra [83]3 years ago
6 0
The north and the south of the globe are magnitized and the needles of a compass are magnetized. Since positives attract negatives. The negative end of the earth attarcts the positive point of the needle to point towards it. The same happens with positive end of the earth and the negative point of the needle.
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The thermal emission of the human body has maximum intensity at a wavelength of approximately 9.5 μm.What photon energy correspo
tatuchka [14]

Answer:

Explanation:

2.1 x 10^2 - 20J

8 0
2 years ago
A car starting from rest accelerates in a straight line at a constant rate of 5.5m/s for 6s.If the car after this acceleration s
aalyn [17]

Answer:

The time it takes to stop is 13.75 seconds

Explanation:

A body moving with constant acceleration, 'a', for a time, 't', has a final velocity, 'v', given by the following kinematic equation;

v = u + a·t

Where;

v = The final velocity of the body

a = The acceleration of the body

t = The time of acceleration (accelerating period) of the body

u = The initial velocity of the body

The given parameters for the acceleration of the car are;

The initial velocity of the car, u = 0 m/s (a car starting from rest)

The constant acceleration of the car, a =  5.5 m/s²

The acceleration duration, t = 6 s

Therefore, we have;

The final velocity of the car after the acceleration, v = 0 m/s + 5.5 m/s² × 6 s = 33 m/s

The final velocity of the car after the acceleration, v = 33 m/s

When the car slows down uniformly, and comes to a stop (final velocity, v₂ = 0 m/s), it has a constant negative acceleration, (deceleration) '-a₂'

The given parameters when the car slows down  are;

The deceleration, -a₂ = 2.4 m/s²

The final velocity, v₂ = 0 m/s

The initial velocity, u₂ = v = 33 m/s

The time it takes to stop = t₂

-a₂ = 2.4 m/s²

∴ a₂ = -2.4 m/s²

From, v = u + a·t, we have;

v₂ = v + a₂·t₂

By plugging in the values of the variables, we have;

0 m/s = 33 m/s + (-2.4 m/s²) × t₂

∴ 2.4 m/s² × t₂ = 33 m/s

t₂ = 33 m/s/(2.4 m/s²) = 13.75 s

The time it takes to stop, t₂ = 13.75 seconds

7 0
3 years ago
The volume of a gas is reduced from 4 l to 0.5 l while the temperature is held constant. How does the gas pressure change?
shusha [124]

Answer:

The pressure increases by a factor 8

Explanation:

For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:

p_1 V_1 = p_2 V_2

where

p_1 is the initial pressure

p_2 is the final pressure

V_1 is the initial volume

V_2 is the final volume

For the gas in this problem, the volume is reduced from

V_1 = 4 L

to

V_2 = 0.5 L

so we can rewrite the equation as

\frac{p_2}{p_1}=\frac{V_1}{V_2}=\frac{4 L}{0.5 L}=8

this means that the pressure of the gas will increase by a factor 8.

5 0
4 years ago
An alpha particle (charge = +2.0e) is sent at high speed toward a gold nucleus (charge = +79e). What is the electric force actin
umka2103 [35]

Answer:

F = 91.27 N

Explanation:

Parameters given:

Charge of alpha particle, q = +2.0e = 2.0 * 1.60217662 * 10^{-19} = 3.204 * 10^{-19} C

Charge of gold nucleus, Q = +79e = 79 * 1.60217662 * 10^{-19} = 1.266 * 10^{-17} C

Distance between the alpha particle and gold nucleus, r = 2.0 * 10^{-14} m

Electric force is given as:

F = \frac{kqQ}{r^2}

where k = Coulomb's constant

Therefore:

F = \frac{9 * 10^9 * 3.204 * 10^{-19} * 1.266 * 10^{-17}}{(2.0 * 10^{-14})^2} \\\\\\F = 91.27 N

The electric force acting on the alpha particle when the alpha particle is 2.0 * 10^{-14} m from the gold nucleus is 91.27 N.

7 0
3 years ago
Drag and drop the correct answer to complete the sentence.
Afina-wow [57]

Answer: 10kg

Explanation:

force applied by Ahmad = 100 N

box's acceleration = 10 m/s

mass of the box = ?

Recall that Force is the product of mass of an object by the acceleration by which it moves.

i.e Force = mass x acceleration

100N = mass x 10m/s

Mass = 100N / 10m/s

Mass = 10kg

Thus, the mass of the box is​ 10kg

6 0
3 years ago
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