Solve the right triangle. Round decimal answer to the nearest 10th

Mathematics

1 answer:

kotegsom [21]3 years ago

6 0

Cos ∠A = adj/hyp
∠A = cos⁻¹ (adj/hyp)
∠A = cos⁻¹ (10/15)
∠A = 48.2° (nearest tenth)

sin ∠B = opp/hyp
∠B = sin⁻¹ (opp/hyp)
∠B= sin⁻¹ (10/15)
∠B = 41.8°(nearest tenth)

a² + b² = c²
BC² + 10² = 15²
BC² = 15² - 10²
BC² = 125
BC = √125
BC = 11.2 units (nearest tenth)

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