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Anna007 [38]
3 years ago
15

Solve the right triangle. Round decimal answer to the nearest 10th

Mathematics
1 answer:
kotegsom [21]3 years ago
6 0
Cos ∠A = adj/hyp 
∠A = cos⁻¹ (adj/hyp)
∠A = cos⁻¹ (10/15)
∠A = 48.2° (nearest tenth)

sin ∠B = opp/hyp
∠B = sin⁻¹ (opp/hyp)
∠B= sin⁻¹ (10/15)
∠B = 41.8°(nearest tenth)

a² + b² = c²
BC² + 10² = 15²
BC² = 15² - 10²
BC² = 125
BC = √125
BC = 11.2 units (nearest tenth)


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The 5.25 m combined height of John, Jim, and Joe, the 12 cm height difference between John and Jim and the 0.09 m difference in height between Jim and Joe, indicates that solution to the word problem is Joe was 1.73  meters tall

<h3>What is a word problem?</h3>

A word problem is a presentation of a math problem using verbal description rather than numbers, variables and operators.

The combined height of John, Jim and Joe = 5.25 m

John's height = Jim's height - 12 cm = Jim's height - 0.12

Jim's height = Joe's height + 0.09 m

Let <em>h </em>represent Joe's height, we get;

Jim's height = h + 0.09

John's height = h + 0.09 - 0.12 = h - 0.03

John's height = h - 0.03

The sum of the heights is therefore; h + h + 0.09 + h - 0.03 = 3·h + 0.06

The sum of their heights = Their combined height = 5.25 meters

Therefore; 3·h + 0.06 = 5.25

h = (5.25 - 0.06)/3 = 1.73

Joe's height, <em>h</em> = 1.73 meters

Jim's height = 1.73 + 0.09 = 1.82

Jim's height = 1.82 meters

John's height = 1.73 - 0.03 = 1.7

John's height is 1.7 meters

Joe was 1,73 meters tall

Learn more about mathematics word problems?

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