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3 years ago

Solve the right triangle. Round decimal answer to the nearest 10th

Mathematics

1 answer:

kotegsom [21]3 years ago

6 0

Cos ∠A = adj/hyp
∠A = cos⁻¹ (adj/hyp)
∠A = cos⁻¹ (10/15)
∠A = 48.2° (nearest tenth)

sin ∠B = opp/hyp
∠B = sin⁻¹ (opp/hyp)
∠B= sin⁻¹ (10/15)
∠B = 41.8°(nearest tenth)

a² + b² = c²
BC² + 10² = 15²
BC² = 15² - 10²
BC² = 125
BC = √125
BC = 11.2 units (nearest tenth)

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There are 476 students plus 35 sponsors

476+35=511

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3 years ago

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4 years ago

513 as a percentage of 900

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3 years ago

Find the area of the following shape. You must show all work to receive credit

kirza4 [7]

Answer:

42 square units

Step-by-step explanation:

Draw segments - 5 to A, A to the point of intersection of Band C and from from the point of intersection of B, C upto 2. It will form a square with each side 8 units and four triangles.

Subtracting the area of 4 four triangles from the area of the square will give you the area of the required shape.

Area of the shape

$= {8}^{2} - \frac{1}{2} \times 3 \times 6 - \frac{1}{2} \times 5 \times 2 - \frac{1}{2} \times 2 \times 3\\ - \frac{1}{2} \times 2 \times 5 \\ \\ = 64 - 3 \times 3 - 5 \times 1 - 1\times 3 - 1 \times 5 \\ \\ = 64 - 9 - 5 - 3 - 5 \\ \\ = 64 - 22 \\ = 42 \: {units}^{2}$

3 0

3 years ago

Read 2 more answers

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$

$(x^2-1)+(y^2-(-2))=16$

Now, we have that:

$h=1\\k=-2\\r=\sqrt{16}=4$

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0

4 years ago