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Dafna1 [17]
3 years ago
6

It costs $12 to enter the fair and $0.50 per ticket for rides. How much total would you spend if you paid admission and bought 7

0 tickets? plz hurry will mark brainlest
Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

The initial cost is $12 to enter.

Each ticket is $.50

we want to find out how much it costs for 70 tickets so we multiply the cost by the amount;

70 x .50 = 35

Therefor including the entry fee, it would cost $35 + $12

Which is $47

I hope this helps! :)

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Ming has 15 quarters, 30 dimes, and 48 nickels. He wants to group his money so that each group had the same number of each coin.
Colt1911 [192]
Find the greatest common factor. In this case it is 3. Divide each group by 3.
15÷3=5 quarters
30÷3=10 dimes
48÷3=16 nickels
Next count them by the coin's value:
5 × 0.25 = $1.25
10 × 0.10 = $1
16 × 0.05 = $0.80
Add them up:
= $3.05 in each group and there are three groups.

So, the greatest number of groups that he can make is 3; there will be 5 quarters, 10 dimes, and 16 nickels in each group, which is worth $3.05 in each group.
3 0
3 years ago
15 POINTS PLEASE HELP!!! WILL MARK BRAINLIEST
dangina [55]

Given: ∠ DEF

To construct: ∠TSZ ≅ ∠DEF

Construction: Consider the attachment

Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST

Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.

Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.

Step-04: Now, join the point SQ and extend up to Z such that EF = SZ

Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF

6 0
3 years ago
suppose that a certain basketball athlete earned $23,000,000 to play 80 games, each last 48 min. how much did the athlete earn p
Anit [1.1K]
He earns 23 000 000 per 80 games for 48min
Per game he earns
23000000 \div 8 0 = 782500
If he earns 782 500 per game he earns 5 989,5833 per minute

782500 \div 48 = 5989.5833
If he played 2/3 of the time he played 32min which means he earned...

782500 \div 32 = 24453.125
So he trained 35hours for a 48min match
Together that is 35.8hours

But I dont think this really matters here you just have to multiply 24453.125 with 60

And you get his hourly salary which is 1 467 187.5

5 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED HELP ASAP TRANSVERSAL ANGLES A LOT OF POINTS ON THE LINE.
guapka [62]

Answer:

Step-by-step explanation:

so basically you have to look for the opposite side of what they give you. then just plot it in

5 0
3 years ago
Suppose that you take a sample of 250 adults. If the population proportion of adults who watch news videos is 0.58​, what is the
aliina [53]

Answer:

0.36% probability that fewer than half in your sample will watch news​ videos

Step-by-step explanation:

To solve this question, i am going to use the binomial approximation to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 250, p = 0.58

So

\mu = E(X) = 250*0.58 = 145

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{250*0.58*0.42} = 7.80

If the population proportion of adults who watch news videos is 0.58​, what is the probability that fewer than half in your sample will watch news​ videos

Half: 0.5*250 = 125

Less than half is 124 or less

So this is the pvalue of Z when X = 124

Z = \frac{X - \mu}{\sigma}

Z = \frac{124 - 145}{7.8}

Z = -2.69

Z = -2.69 has a pvalue of 0.0036

0.36% probability that fewer than half in your sample will watch news​ videos

8 0
3 years ago
Read 2 more answers
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