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natita [175]
3 years ago
13

A convex hexagon has interior angles with measures x^0, (5x - 103); (2x + 60), (7x - 31), (6x -6), and (9x - 100), what is the v

alue of x?
Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

x = 30.66°

Step-by-step explanation:

The sum of the interior angles of a hexagon is 720°

Each angles are x^0, (5x - 103); (2x + 60), (7x - 31), (6x -6), and (9x - 100),

we add all these angles together

x^0 + (5x - 103) + (2x + 60) + (7x - 31) + (6x -6) + (9x - 100) = 720

x^0  = 1

1 + (5x - 103) + (2x + 60) + (7x - 31) + (6x -6) + (9x - 100)

1 + 5x - 103 +2x + 60 + 7x -31 + 6x - 6 + 9x - 100 = 720

1 - 103 + 60 - 31 - 6 - 100 + 5x + 2x + 7x + 6x + 9x = 720

1 - 180 + 29x = 720

-179 + 29x = 720

29x = 720 + 179 = 889

x = 889/29 = 30.655 ≅ 30.66°

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Answer:

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Step-by-step explanation:

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Find the equations of the lines for the following. Your answer should be in the form y=mx+b.
spin [16.1K]

Answer:

1 ) y = 2x - 1

slope = 2

y intercept is (0,-1)

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slope = -0.5

y intercept  = (0,5)

Step-by-step explanation:

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Could someone help with the questions in the images below? I found them difficult
zubka84 [21]
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
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Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
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Now you have all the data needed for the box plot.

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Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
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Draw another one down to help you read the number.
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Remember, LQ = n/4
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To work out the UQ, we multiply the LQ place by 3 3(n/4).
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30 on the graph takes us up to 45 seconds.

We now know that the:
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With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
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The boy IQR = 45 - 16 = 29
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Step-by-step explanation:

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