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nydimaria [60]
4 years ago
13

Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, a

nd the length is 5 feet more than twice the width. The perimeter of the lawn is 250 feet. Homework Help ✎
Use the 5-D Process to find the dimensions of the lawn.

Use the dimensions you calculated in part (a) to find the area of the lawn.

What are the answers and how do i solve it thank you
Mathematics
1 answer:
Bogdan [553]4 years ago
7 0

Answer:

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 feet^2

Step-by-step explanation:

Given: Lawn is rectangular in shape

          Length of lawn is 5 feet more than twice its breath/width

           Perimeter of Lawn = 250 feet

To find: (a) Length and width of lawn

             (b) Area of Lawn

First let the a variable for width/breadth. Say, Width = b.

So, the length of lawn = 2b + 5

Perimeter of Rectangle = 2 × ( length + width )

Now, substitue given values in this formula

∴ Perimeter of Lawn = 2 × ( 2b + 5 + b )

250 = 2\times{(2b+b+5)}\\250= 2\times{(3b+5)}\\3b+5 = \frac{250}{2}\\3b = 125 -5\\3b = 120\\b=\frac{120}{3}\\b=40

∴width = 40 feet

⇒ length = 85 feet

Now we find are of lawn using formula of area of rectangle

Area of lawn = length × width

                     = 85 × 40

                     = 3400 feet^2

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 feet^2

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Whats the simflied for 6x-2(3x-4)​
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Please need help for 1-9
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3 0
3 years ago
In the diagram below, R is located at (24,0), N is located at (12,18), T is located at (12,6), and E is located at (18,15). Assu
julsineya [31]

The midpoint of a segment divides the segment into equal halves

  • The coordinates of K are: \mathbf{K = (12,12)}
  • The coordinates of I are: \mathbf{I = (24,24)}
  • The coordinates of B are: \mathbf{B = ( 30,33 )}

The given parameters are:

\mathbf{R =(24,0)}

\mathbf{N =(12,18)}

\mathbf{T =(12,6)}

\mathbf{E =(18,15)}

K is the midpoint of N and T.

So, we have:

\mathbf{K = (\frac{N_x + T_x}{2},\frac{N_y + T_y}{2})}

This gives

\mathbf{K = (\frac{12 + 12}{2},\frac{18+ 6}{2})}

\mathbf{K = (12,12)}

E is the midpoint of T and I.

So, we have:

\mathbf{E = (\frac{I_x + T_x}{2},\frac{I_y + T_y}{2})}

This gives

\mathbf{(18,15) = (\frac{I_x + 12}{2},\frac{I_y+ 6}{2})}

Multiply through by 2

\mathbf{(36,30) = (I_x + 12,I_y+ 6)}

By comparison

\mathbf{I_x + 12 = 36.\ I_y + 6 =30}

So, we have:

\mathbf{I_x= 24.\ I_y  =24}

Hence, the coordinates of I are:

\mathbf{I = (24,24)}

I is the midpoint of E and B.

So, we have:

\mathbf{I = (\frac{E_x + B_x}{2},\frac{E_y + B_y}{2})}

This gives

\mathbf{(24,24) = (\frac{18 + B_x}{2},\frac{15 + B_y}{2})}

Multiply through by 2

\mathbf{(48,48) = (18 + B_x,15 + B_y)}

By comparison

\mathbf{18 + B_x = 48,\ 15 + B_y = 48 }

So, we have:

\mathbf{B_x = 30,\  B_y = 33 }

Hence, the coordinates of B are:

\mathbf{B = ( 30,33 )}

Read more about midpoints at:

brainly.com/question/18068617

7 0
3 years ago
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