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Cerrena [4.2K]
3 years ago
11

Explanation. Please Help!!!

Mathematics
1 answer:
Svetach [21]3 years ago
8 0

Answer:

The domain is y > 3

Step-by-step explanation:

y = 2⁻ˣ + 3

As x approaches -∞, y approaches ∞.

As x approaches ∞, y approaches 3.

So the range is y > 3, and there is an asymptote at y = 3.

Compared to the parent function y = 2ˣ, it is reflected over the y-axis and shifted up 3 units.

The false statement is "the domain is y > 3".  Domain describes the possible values of x.  Range describes the possible values of y.

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What is the value of x in the equation 3x-1/9y=18, when y=27?
natulia [17]

Hi Vanessa


3x -1/9 (27) =18

3x - 27/9 =18

3x- 3 =18

Add 3 to both sides

3x-3+3=18+3

3x=21

Divide both sides by 3

3x/3= 21/3

x= 7

The value of x is 7


Now let's check if my answer is correct

To check it we gonna replace x by 7 and 27 for y

(3)(7) -1/9 (27) = 18

21 -1/9 (27)=18

21- 27/9 = 18

21- 3 = 18

18 = 18


The answer is good and I hope its help:0

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Absolute value hope this helps
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A theater has 20 rows of chairs. The first row has 16 chairs, the second has 18, the third has 20, and so on. In total, the thea
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A public health organization reports that 40%of baby boys 6-8 months old in the United
Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

  • 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
  • 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
  • Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

P(X > 4) = 1 - P(X \leq 4)

In which:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061

P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403

P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150

P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502

Hence:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106

P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016

P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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The constant of <u>p</u><u>r</u><u>o</u><u>p</u><u>o</u><u>r</u><u>t</u><u>i</u><u>o</u><u>n</u> is the value that relates two variables that are directly proportional or inversely proportional.

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