Hi Vanessa
3x -1/9 (27) =18
3x - 27/9 =18
3x- 3 =18
Add 3 to both sides
3x-3+3=18+3
3x=21
Divide both sides by 3
3x/3= 21/3
x= 7
The value of x is 7
Now let's check if my answer is correct
To check it we gonna replace x by 7 and 27 for y
(3)(7) -1/9 (27) = 18
21 -1/9 (27)=18
21- 27/9 = 18
21- 3 = 18
18 = 18
The answer is good and I hope its help:0
Absolute value hope this helps
I would do it in Buhh I'm working so add all of them(16,18,20) together 6 times then add another 16 and 18 and you will get your answer.
Using the binomial distribution, the probabilities are given as follows:
- 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
- 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
- Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
The values of the parameters for this problem are:
n = 10, p = 0.4.
The probability that more than 4 weigh more than 20 pounds is:

In which:

Then:






Hence:


0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
The probability that fewer than 3 weigh more than 20 pounds is:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673
0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
For more than 7, the probability is:





Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
The constant of <u>p</u><u>r</u><u>o</u><u>p</u><u>o</u><u>r</u><u>t</u><u>i</u><u>o</u><u>n</u> is the value that relates two variables that are directly proportional or inversely proportional.
- <em>O</em><em>p</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>B</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em>!</em><em>!</em><em>~</em>