⅚. You first find out how many feet are in a yard (three). Then you write the fraction- 10/12. Then you reduce. The number two can evenly go into both of those numbers. Ten divided by two is five. Twelve divided by two is six. So, your final answer is ⅚.
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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The correct answer would be 61.32
Answer
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Do reciprical and multiply
Complementary angels add up to 90°
so x+18°=90°
so x=90-18=72°
