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3 years ago

Find the measure of an angle with measure between 0 and 360 that is conterminal with an angle measuring -800

Mathematics

2 answers:

Aleks [24]3 years ago

7 0

Subtract 360 - 80

The answer is 280°.

igomit [66]3 years ago

5 0

Add 720 degrees (which represents two full revolutions around the center) to -800. Result: -80 degrees. This angle is in Quadrant IV.

Subtracting 80 from 360 will give you a positive angle co-terminal with -800 deg. 360 - 80 = ?

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.

Mars2501 [29]

Answer

-1 x + 2y = 4

Explanation

The first step is to get the gradient of the line.

The two points in the line are; (4,0) and (0,2).

slope = (2 - 0)/(0 - 4)

= 2/-4

= -1/2

To get the function we use one of the point (0,2) and a general point (x,y).

1/2 = (y - 2)/(x - 0)

1/2 = (y - 2)/x

(1/2)x = y -2

x = 2y - 4

x - 2y = -4

-1 x + 2y = 4

3 0

3 years ago

Plz help me we are almost done

shusha [124]

Answer: 1. A 2. 1/5 3. 5/12 4. Not sure

Step-by-step explanation:

8 0

3 years ago

Unit 7: Polygons and Quadrilaterals Homework 6: Kites Need Help Stat PLEASE HELP!!!!! 20 POINTS

balu736 [363]

1) The measures of angles H and F are 121°, respectively.

2) The measures of angles U and V are 65° and 139°, respectively.

3) The missing angles are $m \angle 1 = 72^{\circ}$ , $m\angle 2 = 72^{\circ}$ , $m\angle 3 = 47^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m\angle 5 = 18^{\circ}$ , $m\angle 6 = 47^{\circ}$ and $m\angle 7 = 43^{\circ}$ .

4) The missing angles are $m \angle 1 = 55^{\circ}$ , $m\angle 2 = 35^{\circ}$ , $m\angle 3 = 35^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m \angle 5 = 55^{\circ}$ , $m \angle 6 = 67^{\circ}$ , $m\angle 7 = 67^{\circ}$ , $m\angle 8 = 23^{\circ}$ and $m \angle 9 = 23^{\circ}$ , respectively.

5) The measure of side $QT$ is $\sqrt{105}$ .

6) The measure of side $DF$ is $4\sqrt{26}$ .

7) The measure of side $NP$ is $3\sqrt{65}$ .

8) The value of $x$ is 17.

9) The value of $x$ is 6.

10) The measure of angle EDC is 107°.

11) The measure of angle RST is 122°.

<h3>How find missing angles and sides in rhombuses</h3>

1) According to geometry, the sum of internal angles in a quadrilateral equals 360°. Since the given figure is a kite-type rhombus, the measures of angles H and F are 121°, respectively. $\blacksquare$

2) According to geometry, the sum of internal angles in a quadrilateral equals 360°. Since the given figure is a kite-type rhombus, the measures of angles U and V are 65° and 139°, respectively. $\blacksquare$

3) According to geometry, the sum of internal angles in a triangle equals 180° and the sum of internal angles in a quadrilateral equals 360°. The missing angles are $m \angle 1 = 72^{\circ}$ , $m\angle 2 = 72^{\circ}$ , $m\angle 3 = 47^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m\angle 5 = 18^{\circ}$ , $m\angle 6 = 47^{\circ}$ and $m\angle 7 = 43^{\circ}$ , respectively. $\blacksquare$

4) According to geometry, the sum of internal angles in a triangle equals 180° and the sum of internal angles in a quadrilateral equals 360°. The missing angles are $m \angle 1 = 55^{\circ}$ , $m\angle 2 = 35^{\circ}$ , $m\angle 3 = 35^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m \angle 5 = 55^{\circ}$ , $m \angle 6 = 67^{\circ}$ , $m\angle 7 = 67^{\circ}$ , $m\angle 8 = 23^{\circ}$ and $m \angle 9 = 23^{\circ}$ , respectively. $\blacksquare$

5) In this case we need to apply Pythagorean theorem and triangle and quadrilateral properties to determine the missing side:

$QT = \sqrt{PQ^{2}-PT^{2}}$

$QT = \sqrt{13^{2}-8^{2}}$

$QT = \sqrt{105}$

The measure of side $QT$ is $\sqrt{105}$ . $\blacksquare$

6) In this case we need to apply Pythagorean theorem and triangle and quadrilateral properties to determine the missing side:

$DF = 2\cdot DH$ , $DH = \sqrt{DE^{2}-EH^{2}}$

$DF = 2\cdot \sqrt{DE^{2}-EH^{2}}$

$DF = 2\sqrt{15^{2}-11^{2}}$

$DF = 4\sqrt{26}$

The measure of side $DF$ is $4\sqrt{26}$ . $\blacksquare$

7) In this case we need to apply Pythagorean theorem and triangle and quadrilateral properties to determine the missing side:

$NK = 7\cdot x - 1$ , $NM = 10\cdot x - 13$ , $KM = 24$ , $NK = NM$ , $KP = \frac{KM}{2}$

$NP = \sqrt{NK^{2}-KP^{2}}$

$NP = \sqrt{[7\cdot (4)-1]^{2}-12^{2}}$

$NP = 3\sqrt{65}$

The measure of side $NP$ is $3\sqrt{65}$ . $\blacksquare$

8) According to geometry, the sum of internal angles in a quadrilateral equals 360°. Since the given figure is a kite-type rhombus, the value of $x$ is 17. $\blacksquare$

9) According to geometry, the sum of internal angles in a quadrilateral equals 360°. Since the given figure is a kite-type rhombus, the value of $x$ is 6. $\blacksquare$

10) According to geometry, the sum of internal angles in a triangle equals 180°. Hence, we have the following expressions:

$m\angle EDC = 180^{\circ}-90^{\circ}-[2\cdot (2)+13]$

$m\angle EDC = 107^{\circ}$

The measure of angle EDC is 107°. $\blacksquare$

11) According to geometry, the sum of internal angles in a triangle equals 180°. Hence, the angle RST is:

$m\angle RST = 2\cdot (3\cdot 12 +25)$

$m \angle RST = 122^{\circ}$

The measure of angle RST is 122°. $\blacksquare$

To learn more on quadrilaterals, we kindly invite to check this verified question: brainly.com/question/25240753

8 0

3 years ago

Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at 5 dollars each.

kakasveta [241]

Here is the inequality you can enumerate:

5x >= 200, this means the money you sold for cakes must be larger or equal to your goal

x <= 100, this means you cannot sell more than 100 cakes, because you only have 100 cakes

Solve for them, you will get: 40 <= x <= 100

5 0

4 years ago

D 5/3 Couldn’t fit in pic

labwork [276]

Answer:

Step-by-step explanation:

You can just move upper y equation and it will be:

6x+3(3x-5)=15

6x+9x-15=15

15x-15=15

15x=30

x=2

6 0

3 years ago

Read 2 more answers