Answer:
131.25 in ^2
Step-by-step explanation:
Find the area of the rectangle on the left
A = l*w
A = 11.75 * 6 = 70.5 in ^2
Now find the area of the rectangle on the right
The length is 9 and the height is 11.75 - 5 = 6.75
A = 9 * 6.75
A = 60.75 in ^2
Add the areas together
70.5+60.75 = 131.25 in ^2
Answer:
I think it is A, but i am not sure, sorry
Step-by-step explanation:
Two events are independent if the result of the second event is not affected by the result of the first event. If A and B are independent events, the probability of both events occurring is the product of the probabilities of the individual events.
A. For independent events, find the probability of the first event, find the probability of the second event after the first event occurs, and then multiply. For dependent events, find the probability of the first event, find the probability of the second event, and then multiply.
Write out all the solutions from 1 to 10 and add them together
(1^2+3(1)-2)=2
(2^2+3(2)-2)=8
" = 16
" = 32
" = 38
" = 52
" = 68
" = 86
" = 106
" = 128
Add them together: 530
Hope I helped :)
<u>Answer</u>:
Angle A = 17°, Angle B = 73°
<u>Step-by-step explanation:</u>
Angle A & Angle B are complementary angles (given) so they will form 90°.
Let's take,
Angle A = x
Angle B = 4x +5 (angle B is five degrees more than four times angle A)
Measure of each angle=?
Angle A + Angle B = 90°
x + 4x + 5 = 90
5x + 5 = 90
5x = 90 - 5
5x = 85
x = 85 ÷ 5
x = <u>1</u><u>7</u><u>°</u>
Angle A = x = <u>1</u><u>7</u><u>°</u>
Angle B = 4x + 5 = 4(17) + 5 = 68 + 5 = <u>7</u><u>3</u><u>°</u>
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Answer: Adenike scored 64 marks, while Musa scored 45 marks
Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.
First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as
3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;
d = 19 + m ———(1)
3d/2 = 6 + 2m ———(2)
Substitute for the value of d into equation (2), if d = 19 + m
(3{19 + m})/2 = 6 + 2m
By cross multiplication we now have
3(19 + m) = 2(6 + 2m)
57 + 3m = 12 + 4m
We collect like terms and we have
57 - 12 = 4m - 3m
45 = m
We now substitute for the value of m into equation (1)
d = 19 + m
d = 19 + 45
d = 64
So Adenike scored 64 marks while Musa scored 45 marks
