Question

Solve the following system of equations: x − 2y = 6 2x − 4y = 10

Answer 1

Question 1)

Solving for x

x−2y=6

Add 2y to both sides.

x−2y+2y=6+2y

x =2y+6

Solving for y.

x−2y=6

 Add -x to both sides.

x−2y+−x=6+−x

−2y=−x+6

Divide both sides by -2

−2y / −2=−x+6 / −2

y =1/2x −3

Question 2)

Solving for x

2x−4y=10

Add 4y to both sides.

2x−4y+4y=10+4y

2x=4y+10

 Divide both sides by 2.

2x/2=4y+10/2

x=2y+5

Solving for y.

2x−4y=10

Add -2x to both sides

2x−4y+−2x=10+−2x

−4y=−2x+10

Divide both sides by -4.

−4y / −4=−2x+10 / −4

y =1 / 2 x + −5 / 2