Ask question

Ask question

All categories

3 years ago

10

Rename the number 8 hundreds 4 tens = 84

1 answer:

Readme [11.4K]3 years ago

5 0

Rename the number 8 hundreds 4 tens=84
840 is your answer, Hope I helped!

You might be interested in

Please explain your answer

Irina18 [472]

$\text{Distance = } \sqrt{(5 + 8)^2+ (-3 + 3)^2 }= \sqrt{13^2} = 13$

Answer: 13 units

6 0

3 years ago

Directions: Show ALL work. NO WORK=NO CREDIT!

Savatey [412]

Answer:

$18.75

Step-by-step explanation:

75 divided among the 4 sisters equally

8 0

3 years ago

Read 2 more answers

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

Write an addition problem that has 9/10 as the sum

kicyunya [14]

There are a number of different problems that you could do that will give you an outcome of 9/10
For example, 1/2 and 2/5 add up to 9/10.
3/10 and 6/10 also add up to 9/10.

Find the sum of 7/10 and 1/5
Find the sum of 7/20 and 11/20
Find the sum of 1/2 and 3/10 and 1/10
Find the sum of 1/5 and 2/5 and 3/10

Hope this helps :)

3 0

3 years ago

Use prime factor decomposition to find the Hcf of 99 and 165

const2013 [10]

Answer:

HCF = 33.

Step-by-step explanation:

99 = 3*3*11

165 = 3*5*11

3 and 11 are common so the HCF = 3*11

= 33.

5 0

3 years ago