Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get 
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
35 99/100 (35 wholes 99 over 100)
Answer:
The confidence interval becomes wider.
Step-by-step explanation:
The general form of a confidence interval is:
The critical value is based on the confidence level.
The confidence level is the probability that the true parameter value falls within a specific interval. The basic and most used confidence levels are 90%, 95% and 99%.
The confidence interval is directly proportional to the confidence interval.
Confidence Interval ∝ Confidence Level
On increasing the confidence level the confidence level widens. And on decreasing the confidence level the confidence level gets narrower.
Thus, when Gina changes the confidence interval to 99% the confidence interval becomes wider.
Answer: ![\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B3%7D%5B%5Cln%20%28x%2B1%29%2B%5Cln%28x-1%29%5D)
Step-by-step explanation:
Properties of logarithm :
The given expression in terms of Natural log : 
This will become 
[ By using Property (3)]
[
]
![=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B3%7D%5B%5Cln%20%28x%2B1%29%2B%5Cln%28x-1%29%5D)
[ By using Property (1)]
Hence, the simplified expression becomes .
Answer:
(0,-22)
Step-by-step explanation:
