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Tomtit [17]
3 years ago
15

Two numbers are randomly selected from integers 1 through 9. What is the probability that only one of the integers is odd given

that the sum of the two numbers is odd?
1/4

1

40/81

5/40
Mathematics
1 answer:
Stells [14]3 years ago
4 0

Another one where there's a danger of overthinking it !

The sum of ANY two integers is odd only if one is even and one is odd.

If they're both odd OR both even, then their sum is even.

So if their sum is odd, then one is odd and the other is even.

The probability is ' 1 ' (100%) .

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Find x and y. <br><br> pls pls help
Anna [14]

Answer:

x = 65 , y = 64

Step-by-step explanation:

y - 16 and 2y + 4 are same- side interior angles and sum to 180° , that is

y - 16 + 2y + 4 = 180

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y = 64

then

2y + 4 = 2(64) + 4 = 128 + 4 = 132

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7 0
1 year ago
Can you help me find the answer to it pls and ty &lt;3 .
grin007 [14]

The expression that represent the area of the cut off part is 81π / 4

<h3>How to find area?</h3>

The area of the cut off part can be found as follows:

Area of a circle = πr²

where

  • r = radius

Therefore, the cut off part is like 1 / 4th of a circle.

Hence,

area of the cut off region = πr² / 4

r = 9 inches

area of the cut off region =  π9² / 4

area of the cut off region = 81π / 4

learn more on area here: brainly.com/question/15403474

#SPJ1

4 0
2 years ago
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