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ludmilkaskok [199]

4 years ago

11

Just after two identical point charges are released when they are a distance D apart in outer space, they have an acceleration a

. If you release them from a distance D/2 instead, their acceleration will be?
a) a/4 b) a/2 c) 2a d) 4a

1 answer:

Darya [45]4 years ago

7 0

Answer:

d) 4a

Explanation:

r = Distance

Electrostatic force is given by

$F=\dfrac{kq_1q_2}{r^2}$

$ma=\dfrac{kq_1q_2}{r^2}$

It can be seen that the force is inversely proportional to distance

$a\propto \dfrac{1}{r^2}$

If the distance is reduced

$\dfrac{a_1}{a_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{a_1}{a_2}=\dfrac{(\dfrac{d}{2})^2}{d^2}\\\Rightarrow \dfrac{a_1}{a_2}=\dfrac{1}{4}\\\Rightarrow a_2=4a_1$

So, the new acceleration will be four times the old acceleration

The answer is d) 4a

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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What

spin [16.1K]

Answer:

The wavelength is $\lambda_ 1 = 574.2 nm$

Explanation:

From the question we are told that

The thickness is $t = 198 nm = 198 *10^{-9 }\ m$

The refractive index of the non-reflective coating is $n_m = 1.45$

The refractive index of glass is $n_g = 1.50$

Generally the condition for destructive interference is mathematically represented as

$2 * n_m * t * cos (\theta) = n * \lambda$

Where $\thata$ $\theta$ is the angle of refraction which is 0° when the light is strongly transmitted

and n is the order maximum interference

so

$\lambda = \frac{2 * n * t * cos (\theta )}{n}$

at the point n = 1

$\lambda _1 = \frac{2 * 1.45 * 198*10^{-9} * cos (0 )}{1}$

$\lambda_1 = 574.2 *10^{-9}$

$\lambda_1 = 574.2 nm$

at n =2

$\lambda _2 = \frac{\lambda _1 }{2}$

$\lambda _2 = \frac{574.2*10^{-9} }{2}$

$\lambda _2 = 2.87 1 *10^{-9} \ m$

$\lambda _2 = 287. 1 nm$

Now we know that the wavelength range of visible light is between

$390 \ nm \to 700 \ nm$

So the wavelength of visible light that is been transmitted is

$\lambda_ 1 = 574.2 nm$

6 0

4 years ago

If you travel 2 miles west then 4 miles south then what is your displacement in meters

Leokris [45]

Answer:

9656.06 meters because youd go 6 miles and 9656.06 is 6 miles but just in meters. I hope this helps :)

Explanation:

5 0

3 years ago

A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.

zalisa [80]

Answer:

$P_{f}$ =(5.7 x $10^{7$ i - 2.24 x $10^{7$ j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

$F= \frac{Gm_{1}m_{2} }{r^{2} }$ r^

Plugging in the values, we have

F= [(6.67x $10^{-11}$ )(1500)(5.97 x $10^{24}$ )(8x $10^{6}$ i + 9x $10^{6$ j)] / ((8x $10^{6}$ )² + (9x $10^{6$ )² $)^{1.5}$

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

$P_{f}$ = $P_{i$ + FΔt

$P_{f}$ = 1500(3.5 x $10^{4$ i - 1.8x $10^{4$ j) + (2736i + 3078j)(1.5x $10^{3$ )

$P_{f}$ =(5.7 x $10^{7$ i- 2.24 x $10^{7$ j)kgm/s

4 0

4 years ago

a radio controlled car rolls 10 m south then reverses direction and rolls 8 m north the car traveled a distance of 18 m and has

EastWind [94]

The displacement is 2 m south

Explanation:

Distance and displacement are two different quantities:

Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points

For the car in this problem, the motion is:

10 m south

8 m north

Taking north as positive direction, we can describe the two parts of the motion as

$d_1 = -10 m$

$d_2 = +8$ m

Therefore, the final position of the car with respect to the original position is

$x_f = -10 + 8 = -2 m$

which means 2 m south: so, the displacement of the car is 2 m south.

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

5 0

3 years ago

What are the signs of a chemical change

Rom4ik [11]

Gas or bubbles are formed
Heat, light, or sound is given off
Change in color
Different taste or smell (never taste or smell anything in a chemical lab, cause if u do bad reactions may occur to your body, unless directed to do so.)
New substance is formed (a precipitate)
<span>Temperature (exothermic or endothermic reactions) ( exothermic RELEASES heat energy) (endothermic ABSORBS energy)</span>

5 0

3 years ago