How many seconds will it take to travel 3,600 meters if your speed is 90 meters per second?

A planet has two moons with identical mass. Moon 1 is in a circular orbit of radius r. Moon 2 is in a circular orbit of radius 2

saw5 [17]

Answer:

Half as large.

Explanation:

Using Newton's law of universal gravitation, if the mass of the planet is M and of the Moons 1 and 2 is m, them the force exerted by the planet on them will be:

$F_1=\frac{GMm}{r}$

$F_2=\frac{GMm}{2r}$

Which clearly shows that the force that the planet exerts on the Moon 2 is half the force it exerts on the Moon 1.

7 0

4 years ago

Young's Modulus refers to changes in the: a- Volume b- Length c- Body layers

bekas [8.4K]

Answer: The correct answer is Option b.

Explanation:

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

Stress is defined as force per unit area and strain is defined as proportional deformation in a material.

The equation representing Young's Modulus is:

$Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}$

where,

Y = Young's Modulus

F = force exerted by the weight

l = length of wire

A = area of cross section

$\Delta l$ = change in length

Hence, the correct answer is Option b.

6 0

4 years ago

You drop a 20 Ton object and a

Alborosie

Explanation:

it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.

i.e

v = u + gt

whte v is final velocity of the object

u is initial velocity of the object

g is acceleration due to gravity and

t is time. thanks

please if found helpful rate brainliest

7 0

2 years ago

A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat

Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is 1215 N

Explanation:

$\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}$

$\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}$

$\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}$

Using Newton's second law, it is established that F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object $\left(m_{1}+m_{2}\right)$

Now consider both $\mathrm{m}_{1} \text { and } \mathrm{m}_{2}$ as a system, so net force acting on the system is $\text { Force }=\left(m_{1}+m_{2}\right) a$

Substitute the given values in the above formula,

$\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

$\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

Force = 1215 N

1215 N is the force required to move the quarterback with linebacker.

5 0

3 years ago

If the current in a wire increases from 5 A to 10 A, what happens to its magnetic field? If the distance of a charged particle f

Anna007 [38]

(1) Doubling of the current through the wire will result in doubling of its magnetic field.

The magnetic field around a wire is a function of the current I and radial distance r

$B = \frac{\mu\cdot I }{2\pi r}$

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A

(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.

(3) Answer

If a particle with a charge q moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

$F_m = B\cdot v\cdot q$

So, a particle with charge -2uC will experience a magnetic force of same magnitude but opposite direction (and perpendicular to B) as compared to a particle with a charge of 2uC

3 0

3 years ago

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