Certain neutron stars (extremely dense stars) are believed to be rotating at about 1000 rev/s. If such a star has a radius of 14
km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation
1 answer:
Answer:
minimum mass of the neutron star = 1.624 × 10^30 kg
Explanation:
For a material to remain on the surface of a rapidly rotating neuron star, the magnitude oĺf the gravitational acceleration on the material must be equal to the magnitude of the centripetal acceleration of the rotating neuron star.
This can be represented by the explanations in the attached document.
minimum mass of the neutron star = 1.624 × 10^30 kg
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Answer:
the speed of the block when it reaches point B is 14 m/s
Explanation:
Given that:
mass of the block slides = 1.5 - kg
height = 10 m
Force constant = 200 N/m
distance of rough surface patch = 20 m
coefficient of kinetic friction = 0.15
In order to determine the speed of the block when it reaches point B.
We consider the equation for the energy conservation in the system which can be represented by:
v = 14 m/s
Thus; the speed of the block when it reaches point B is 14 m/s