Certain neutron stars (extremely dense stars) are believed to be rotating at about 1000 rev/s. If such a star has a radius of 14
km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation
1 answer:
Answer:
minimum mass of the neutron star = 1.624 × 10^30 kg
Explanation:
For a material to remain on the surface of a rapidly rotating neuron star, the magnitude oĺf the gravitational acceleration on the material must be equal to the magnitude of the centripetal acceleration of the rotating neuron star.
This can be represented by the explanations in the attached document.
minimum mass of the neutron star = 1.624 × 10^30 kg
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Answer:
0.02 m
Explanation:
R₁ = initial distance jumped by jumper = 7.4 m
R₂ = final distance jumped by jumper = ?
θ₁ = initial angle of jump = 45°
θ₂ = final angle of jump = 42.9°
= speed at which jumper jumps at all time
initial distance jumped is given as
final distance jumped is given as
Dividing final distance by initial distance
distance lost is given as
d =
d = 7.4 - 7.38
d = 0.02 m