Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and 
Therefore segment NO is parallel to the segment KL.
I think best word to insert in the blank is the term "bisecting".
An altitude of a triangle is a line or segment that passes through a vertex of the triangle and is bisecting <span>to the line containing the opposite side.
</span>"Bisect<span>" means to divide into two equal parts which is true for the altitude of a triangle.</span>
Volume of the cone:
V = 3.14 x 3^2 x 9/3 = 84.78
Volume of half sphere on top of cone:
V = (4/3 x 3.14 x 3^3 )/2 = 56.52
Total volume = 56.52 + 84.78 = 141.3 cm^3
Answer:
y=2.9
Step-by-step explanation:
3(2y - 0.3) = 19.4 - y
6y-0.9=19.4
6y+y-0.9=19.4
6y+y=19.4+0.9
7y=19.4+0.9
7y=20.3
7y/7=20.3/7 (divid each one by seven. that's what /7 means)
y=2.9
Answer:
5.2cm
Step-by-step explanation:
