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Sergeu [11.5K]
3 years ago
15

What is the slope of the line​

Mathematics
2 answers:
Viktor [21]3 years ago
4 0

Answer:

what line?

Step-by-step explanation:

Maurinko [17]3 years ago
3 0

Answer:

y2-y1/x2-x1

Step-by-step explanation:

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If a triangle has a height of 12 in and a base of 5 inbwhats the area
Yuliya22 [10]
Area of a triangle
A=h x b/2=12 x 5/2=30
 please mark me as brainly 

7 0
3 years ago
A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght
expeople1 [14]

Answer:

8.5m^{2}+ m -5

Step-by-step explanation:

Since perimeter, P=19m^{2}+ 2m -10 and we know that P=2(l+w) then P=2(l+m^{2})=2l+2m^{2}

The length will be 2l=19m^{2}+ 2m -10-2m^{2}=17m^{2}+ 2m -10

Now l=8.5m^{2}+ m -5

6 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
Change the following fractions into mixed numbers
Travka [436]
A) 23/8 divide 23 by 8 to get 2 with remainder 7 therefore 2 7/8
work all by treating each fraction as a division problem and placing the remainder over the divisor 
b) 14/3 = 4 2/3
c) 19/11 = 1 8/11
d) 8/7 = 1 1/7
e) 17/9 = 1 8/9
f) 27/8 = 3 3/8
g) 35/5 = 11 2/3
h) 9/4 = 2 1/4


6 0
3 years ago
Find the exact value of tan A in simplest radical form.
spin [16.1K]

Answer:

tan(A) = \frac{2\sqrt{15}}{11}

Step-by-step explanation:

Given:

Right ∆ABC

AB = 61

BC = 60

AC = 11

Required:

Value of tan A in radical form

SOLUTION:

tan(A) = \frac{opposite}{adjacent}

Opposite = 60

Adjacent = 11

tan(A) = \frac{60}{11}

tan(A) = \frac{\sqrt{4*15}}{11}

tan(A) = \frac{2\sqrt{15}}{11}

6 0
3 years ago
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