Given:
wild turkey ; 12 in the first hour and cumulative number increases by 40% per hour
white-tail deer ; 18 in the first hour and 10 deer each hour after that.
wild turkery: 12 * (1.40)^n-1 ; n is the number of hour
white-tail deer: 18 + 10^n-1 ; n is the number of hour
n wild turkey white-tail deer
1 12 18
2 17 28
3 24 38
4 33 48
5 46 58
6 65 68
7 90 78
It would be hour 7 after sunrise that the cumulative count of the turkeys first exceed the cumulative count of the deer.
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:250
Step-by-step explanation: