There are 25 desks in a classroom. The number of rows is five less than twice the number of desks in each row. Find the number o f rows and the number of desks in each row.
1 answer:
Let's say each row has x desks and there are y rows. We then know that x*y =25 We also know that x*2-5=y (number number of rows is five less than twice the number of desks in each row) So we substitute: x*(x*2-5)=25 putting numbers out of the brackets: 2x*x-5x=25 2x*x-5x-25=0 (2x+5)(x-5)=0 (this bracketing is true: you can check it by expanding it: 2x*x-10x+5x-25 So that means that either x=-2.5which can't be : there can't be a fractional number of benches, or x=5 so each row has 5 desks and there are 2*5-5 rows, or 5 rows.
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Answer:
Step-by-step explanation:
5 3/4 + 2 1/2
Add the whole numbers first
5 + 2
Add the fractions next
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there must be subtraction of multiplication of each two diagonal,
|G|=[12×2-(-6)×0]
=(24+0)
=24ans
Answer:
<h2>-23/13 - 2/13i</h2>
Step-by-step explanation: