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Sati [7]
3 years ago
14

Please help if you answer and some extra points!

Mathematics
1 answer:
andrey2020 [161]3 years ago
5 0

Answer: if you go to symbolab it will definitely help you and yes i know i did not help whatsoever but just try it if not im sorry

Step-by-step explanation:

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What is the total amount that Mathews bank will receive after lending him 8000 for four years
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Answer:

32,000

Step-by-step explanation:

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3 years ago
0.8) 498 what is the answer​
Lina20 [59]

Step 1: We make the assumption that 498 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=498$100%=498​.

Step 4: In the same vein, $x\%=4$x%=4​.

Step 5: This gives us a pair of simple equations:

$100\%=498(1)$100%=498(1)​.

$x\%=4(2)$x%=4(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{498}{4}$

100%

x%​=

498

4​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{4}{498}$

x%

100%​=

4

498​​

$\Rightarrow x=0.8\%$⇒x=0.8%​

Therefore, $4$4​ is $0.8\%$0.8%​ of $498$498​.

7 0
3 years ago
A carnival costs $10.50 to enter plus an additional $3.50 per ticket rides and food.
Digiron [165]

Answer:

A:y=10.50+3.5x

B:80.5

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3 years ago
Find −2(−2.8). You may find using a number line to be helpful.
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Step-by-step explanation:

3 0
3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
Phantasy [73]

Answer:

\cos (a-b)=\cos a \cos b+\sin a \sin b

Step-by-step explanation:

 Given : \cos (180^{\circ}-q)=-\cos q

We have to write which identity we will use to prove the given statement.

Consider \cos (180^{\circ}-q)=-\cos q

Take left hand side of given expression \cos (180^{\circ}-q)

We know

\cos (a-b)=\cos a \cos b+\sin a \sin b

Comparing , we get, a= 180° and b = q

Substitute , we get,

\cos (180^{\circ}-q)=\cos 180^{\circ}  \cos (q)+\sin q \sin 180^{\circ}

Also, we know \sin 180^{\circ}=0 and \cos 180^{\circ}=-1

Substitute, we get,

\cos (180^{\circ}-q)=-1\cdot \cos (q)+\sin q \cdot 0

Simplify , we get,

\cos (180^{\circ}-q)=-\cos (q)

Hence, use difference identity to  prove the given result.

7 0
3 years ago
Read 2 more answers
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