3 years ago

The 7 digit numbers 74A52B1 and 326AB4C are each multiples of 3. Which of the following could be the value of C?

1 answer:

7 0

The answer is c I know because I had that problem two

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Marta_Voda [28]

Need help in this question asap srry i need points

7 0

3 years ago

schepotkina [342]

I’m not sure but I never went over this

4 0

3 years ago

Mandarinka [93]

Answer:

x= AP, y= GP

Step-by-step explanation:

x = 1, 2, 3, 4, 5 - difference in terms = 1, this is AP

y = 5, 25, 125, 625, 3125 - the ratio of increase= 5, this is GP

7 0

2 years ago

koban [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

denpristay [2]

Answer: 9

Step-by-step explanation:

Given

The function is $x^2-6x+c$

To make it a perfect square, compare it with $(a-b)^2=a^2+b^2-2ab$

Here,

$x=a,\\-6x=-2ab\\\\\therefore b=3$

So, c must be square of b i.e. 9

$x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2$

Therefore, value of c is 9.

3 0

3 years ago