If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then the figure must be a rhombus because it has exactly 2 pairs of congruent angles.
I hope this helps! :)
First, use distributive property on the right half.
2 * 5 = 10
2 * 2n = 4n
4n - 9 = 10 + 4n
Add 9 to both sides
4n = 19 + 4n
Subtract 4n from both sides
0 = 19
But thats not true. Therefore, there is no solution.
Answer:
6
Step-by-step explanation:
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To test for a triangle, the two smallest sides added together have to be greater than the third side.
3.95 + 4.56 > 8.65
8.51 > 8.65
this is false
4.56 + 8.65 > 10.31
13.21 > 10.31
could be it
4.56 + 8.65 > 13.21
13.21 > 13.21
no, this would mean they're equal
4.56 + 8.65 > 20.25
13.21 > 20.25
this is also false
<span>B. 10.31 cm
</span>
P 140 units
A 1200 units^2
Step-by-step explanation:
The length of the rectangle is 20 to -20 = 20 - -20 = 40 units
The width of the rectangle is 20 to -10 = 20 - -10 = 30 units
The perimeter is given by
P = 2 ( l+w) = 2 (40+30) = 2 (70) = 140 units
The area is given by
A = lw = 40*30 = 1200 units^2
