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n200080 [17]
2 years ago
8

In the figure, m∠AOC = m∠BOD. Which property of equality would you use to prove m∠AOB = m∠COD? answers: Question 11 options: A)

Division B) Addition C) Multiplication D) Subtraction

Mathematics
1 answer:
cricket20 [7]2 years ago
4 0

Answer:

Subtraction

Step-by-step explanation:

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A baseball player get on base seven times and strikes out five times during the tournament. What is that experimental have abili
SOVA2 [1]
First you have to make the assumption that these are the only two outcomes. There is also the possibility of hitting the ball and getting out. 

However, if we assume that these are the only two cases, we know that the probability is 58.3%. This is because it has been on base 7 times out of 12. 
6 0
3 years ago
What is the equation of the line that goes through the points (5, 11) and (7,21)?
iragen [17]

Answer:

y = 5x - 14

Step-by-step explanation:

First point coordinates

x₁

5

y₁

11

Second point coordinates

x₂

7

y₂

21

Result

Slope (m)

5

m = 10 / 2 = 5 / 1 = 5

Your function

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Equation: y = 5x - 14.

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2 years ago
What is the general equation of a tilted ellipses not centered at the origin?
ICE Princess25 [194]

The general equation of an ellipse in which case it is not centered at the origin and it is tilted is; (x-h)²/a² + (y-k)²/b² = 1.

<h3>What is the general equation of a tilted ellipses not centered at the origin?</h3>

It follows from the task content that the plane shape in discuss is an ellipse which is described by the characteristics that it is tilted and not centered at the origin.

It follows from convention that the general equation of such an ellipse is;

(x-h)²/a² + (y-k)²/b² = 1.

In which case, such an ellipse has center given as point; (h, k).

Read more on ellipse;

brainly.com/question/16904744

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4 0
2 years ago
How to solve 2^3 * 2^2?
const2013 [10]
(2x2x2)(2x2)
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=2x2x2x2x2
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5 0
3 years ago
Read 2 more answers
Hey need some help quick
Goryan [66]

If z=\pm 15i has to be a solution of the equation, just plug it in:

(\pm 15i)^2 + [1] = 0 \iff -225 + [1] = 0 \iff [1] = 225

So, the solutions of

z^2+225=0

are z=\pm 15i

7 0
3 years ago
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