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yuradex [85]
2 years ago
8

How do I solve 6 x 107 using a property

Mathematics
1 answer:
Anastasy [175]2 years ago
4 0
Use distributivity to split the multiplication
6*107
=6(100+7)
=600+42
=642
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Hi people! Can you help me figure this out? I'll mark brainliest!
Arada [10]

D. 12.5

The equation to find the average rate of change is

\frac{y2 - y1 }{x2 - x1}

To find the average rate of change between points (0,20) and (8,120) you need to plug it into the equation so it'll be

\frac{120 - 20}{8 - 0}

this simplifies to

\frac{100}{8}

which is 12.5

4 0
1 year ago
How can you find a unit rate when given a rate?
ivanzaharov [21]
It depends on the problem really. One example is that you drive 10 miles in 2 hours. So you divide the distance over time to get 10/2 = 5. This means you drove 5 miles per hour (mph). The unit rate for this example is 5 mph.
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3 years ago
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bixtya [17]

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2 years ago
What is the base 2 equivalent of 6010? * 111101 base 2 111100 base 2 110000 base 2 110100 base 2
Nuetrik [128]

Answer:

111100 base 2

Step-by-step explanation:

The conversion of 60 base 10 to base 2

When converting a number from base 10 to base 2, the following steps are taken:

a) The number in base 10 is divided by 2 and the remainder is recorded, this continues until the remainder is less than 2.

b) The remainder from the bottom to the top are arranged so as to get the representation of the number in base 2.

60 base 10 to base 2

60 ÷ 2       =       30  remainder  0

30 ÷ 2       =        15 remainder   0

15 ÷ 2       =         7   remainder   1

7 ÷ 2        =          3  remainder   1

3 ÷ 2        =          1   remainder   1

1 ÷ 2         =          0  remainder   1

The remainder from bottom to top is 111100 base 2.

(60)₁₀ = (111100)₂

4 0
3 years ago
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Aloiza [94]

Answer:

GF=72

Step-by-step explanation:

All triangles in the given figure are similar, from SAS. Notice that marked in the diagram, CD=DE=EF=FA.

For triangle \triangle CGF was base GF, leg CF contains three of these marked segments. In triangle \triangle CHE with base HE, leg CE has two of these marked segments. By definition, similar polygons have corresponding sides in a constant proportion. Therefore, the length of GF must be 3/2 the length of EH. Since the length of EH is given as 48, we have:

GF=\frac{3}{2}EH, \\\\GF=\frac{3}{2}\cdot 48,\\\\GF=\boxed{72}

7 0
2 years ago
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