The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
Find out more information about theoretical probability here:
brainly.com/question/24037367
#SPJ4
Salutations!
Which of the following terms correctly described the figure below.
The following terms are correctly used to describe the figure:
→ Prism. It is a prism because it has same cross section lines down the length.
→ Rectangular solid. It is a rectangular because solid means "3 dimensional shapes".
Hope I helped :D
Answer: I didn't understand
Answer:
Nope! these ratios do not form a proportion
Step-by-step explanation:
if you use a calculator to divide 10/9, you get 1.111 repeating.
if you use a calculator to divide 17/15, you get 1.133 repeating.
<em>since 1.111 does not equal 1.113, </em><em>these ratios are not proportional. </em>
Answer: C) as x → -∞, y → 3
as x→ ∞ , y → ∞
<u>Step-by-step explanation:</u>
see graph
Notice that as x approaches negative infinity (goes to the left), the y value approaches the asymptote of y = 3.
And as x approaches positive infinity (goes to the right), the y-value increases without bound so goes to infinity.