Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer:
Slope =-1/4
Step-by-step explanation:
y=mx+n
Slope=m=(y2-y1)/(x2-x1)
A(-1,19).... x1 =-1, y1=19
B(11,16)..... x2=11, y2=16
Slope=(16-19)/(11-(-1))=(-3)/(11+1)=-3/12=-1/4
To calculate expected value,
We can add up the probability of all possible events.
The 2 possible events are either winning $50 or losing the prize, which is $ - 50
Expected value =
50 x 40 % + (-50) x 60%
= $-10
So the answer is $-10
Answer:
One solution
Step-by-step explanation: