Question

Kristen is wrapping presents for the holidays. She has a box that measures 4 ft. x 2 ft. x 2 ft. How many square feet of wrapping paper does she need to cover the box without overlapping?

Answer 1

You first find the area of one piece. The small squares are 4 and there are two so you have 8 so far. The length of the rectangles are 4 and using the width of the square (2) and you multiply, then you get 8 per rectangle, there are 4 rectangles so the total area of the rectangles are 32 adding the 8 from the squares, you get 40 square feet. (2*2*2)+(4*2*4)=40 square feet. Hope this helped!

Answer 2

Answer:

She needs 40 ft² of wrapping paper to cover the box without overlapping.

Step-by-step explanation:

Consider the provided information.

She has a box that measures 4 ft. x 2 ft. x 2 ft.

We need to find how many square feet of wrapping paper does she need to cover the box without overlapping.

We can find the square feet of wrapping paper by using the formula of surface area:

SA=2lw+2lh+2hw

Use the above formula and substitute l=4, w=2 and h=2

SA=2(4)(2)+2(4)(2)+2(2)(2)

SA=2(8)+2(8)+2(4)

SA=16+16+8

SA=40 ft²

Hence, she needs 40 ft² of wrapping paper to cover the box without overlapping.