2=-17. 3=75. 4=-250. hope this helps
X=number of boys
y=number of girls.
We can suggest the following system of equations:
x+y=33
x/y=3/8
We solve this system of equations by substitution method.
x/y=3/8 ⇒x=3y/8
(3y/8)+y=33
least common multiple=8
3y+8y=33*8
11y=33*8
y=(33*8)/11
y=3*8
y=24
x+y=33
x+24=33
x=33-24
x=9
number of boys /total number of students=9/33=3/11
There are 9 boys and 24 girls in the class.
Answer: C: 9. since 3/11 of the students are boys.
All your doing here is 37-19 adding negative is the same has munising
So 37-19=18
