Please explain how to graph this and how you did it

Mathematics

1 answer:

inysia [295]3 years ago

3 0

So you would start at the origin which is 0 then go down one cause of the -1 and right 2 because of the positive 2

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A rocket releases a satellite into orbit around Earth, The satellite travels at 2000 m/s in 25 seconds. What is the acceleration

Leokris [45]

Answer:

Step-by-step explanation:

The formula to calculate speed is s=d/t. If the distance is 2,000 m/s and the time is 25 seconds, you plug in the numbers into the formula for speed. 2,000/25=80

The satellite's acceleration (speed) is 80.

(I'm not exactly sure what the unit should be for the answer 80, but...) I hope this helps and have a great day!! :3

4 0

3 years ago

HELP!!! 20 POINTS!!! URGENT!!!

VashaNatasha [74]

We know that :

$\clubsuit$ $ln(A) - ln(B) = ln(\frac{A}{B})$

$\clubsuit$ $aln(x) = ln(x)^a$

$\clubsuit$ $ln(A) + ln(B) = ln(AB)$

Using above ideas we can solve the Problem :

⇒ $\frac{3}{8}ln(x + 3) = ln(x + 3)^\frac{3}{8}$

⇒ $ln(x - 3) - ln(x + 3)^\frac{3}{8} = ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}]$

⇒ $4ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}] = ln[\frac{(x - 3)}{(x + 3)^\frac{3}{8}}]^4 = ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}]$

⇒ $\frac{1}{3}lnx + ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}] = ln(x)^\frac{1}{3} + ln[\frac{(x - 3)^4}{(x + 3)^\frac{3}{2}}] = ln[\frac{\sqrt[3]{x}(x - 3)^4}{\sqrt{(x + 3)^{3}}}]$